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3 years ago

14

Explain how you can use base-ten blocks or as a decimal models to find 3.15 divided by 3. Include pictures to support your expla

nation

1 answer:

blondinia [14]3 years ago

3 0

With base-ten blocks ,there would be the 3 units, 1 tens block , and five hundreds cubes

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What is the mean median and mode of 201,201,200,199,199

Rasek [7]

Answer:

the median will be 200.

the mode will be 402 n 398.

the mean will be 400.

8 0

2 years ago

Solve for 2 unknowns : 3a+4b=9 ; 2a+2b=6

BARSIC [14]

Let us take the second equation first
2a + 2b = 6
Dividing both sides by 2 we get
a + b = 3
a = 3 - b
Putting the value of a in the first equation we get
3a + 4b = 9
3(3 - b) + 4b = 9
9 - 3b + 4b = 9
b = 9 - 9
= 0
Now putting the value of b in the second equation we get
a + b = 3
a + 0 = 3
a = 3
So the value of the unknown variable a is 3 and the value of the unknown variable b is 0.

3 0

3 years ago

A shepherd is paid rs.2400 for gazing 18 cows for 5 weeks.How much will be paid for gazing 20 cows for 8 weeks?

lys-0071 [83]

Answer:

Rs. 4266.67(approx) will be paid for gazing 20 cows for 8 weeks.

Explanation:

A shepherd is paid rs. 2400 for gazing 18 cows for 5 weeks .

⇒ Number of money paid for gazing 1 cow for 1 week is, $\frac{2400}{18\times 5} =\frac{400}{15}= \frac{80}{3}$

then,

for gazing 20 cows for 8 weeks is= Rs. $\frac{80}{3}\times (20\times 8)$

Therefore, the amount paid for gazing 20 cows for 8 weeks is, $\frac{80 \times 160}{3} = \frac{12800}{3} = Rs. 4266.66667$ or Rs. 4266.67(approx)

7 0

3 years ago

70 points and i’ll give brainliest!! please answer all the questions on the page! must show work and how you got the answer. ple

Bezzdna [24]

6. One variable only so pretty straightforward.

length-x+4

width-x

x+x+4=80

2x=76

x=38

x+4=42

answer: length 42cm and width 38cm

7. Another money problem!

n-# of nickels

q-# of quarters

n=3+q

0.05n+0.25q=2.85

Substitution works like a charm!

0.05(3+q)+0.25q=2.85

0.15+0.05q+0.25q=2.85

0.3q=2.7

q=9

n=3+q

n=3+9

n=12

answer: 9 nickels and 12 quarters

8. One variable situation again.

Ann's money-2b+9

Betty's money-b

b+2b+9=60

3b=51

b=17

2b+9=43

answer: Ann has $43 and Betty has $17.

9. # of red m&m's-x+1

# of blue m&m's-x

x+1+x=13

x=6

x+1=7

answer: 6 blue and 7 red m&m's

10. a-number of adult tickets

s-number of student tickets

a+s=785 ----> a=785-s

5a+2s=3280

5(785-s)+2s=3280

-3s=-645

s=215

a+s=785

a+215=785

a=570

answer: 215 children tickets and 570 adult tickets

3 0

3 years ago

Find the surface area of each figure.

timurjin [86]

Answer:

For a cylinder of radius R and height H, the surface area is given by:

A = 4*pi*R^2 + H*(2*pi*R)

Where pi = 3.14

We can just use that formula for each one of the given cylinders.

1) We can see that the diameter is 10 yd, and the radius is half of the diameter, then the radius is:

R = 10yd/2 = 5yd

And the height is 3yd, then H = 3yd

Replacing these in the area equation, we get:

A = 4*3.14*(5 yd)^2 + 3yd*(2*3.14*5yd) = 408.2 yd^2

2) Here we can see that the diameter is 24 cm, then the radius is:

R = 24cm/2 = 12cm

And the height is H = 10cm

Then the area is:

A = 4*3.14*(12 cm)^2 + 10cm*(2*3.14*12cm) = 2,562.24 cm^2

3) In this case we have a radius equal to 12 cm, and a height equal to 7 cm, then the area is:

A = 4*3.14*(12 cm)^2 + 7cm*(2*3.14*12cm) = 2,336.16cm^2

4) Here is hard to see the measures, I think that here we have:

diameter = 8m

Then R = 8m/2 = 4m

And the height is also 8m, H = 8m

Then the area is:

A = 4*3.14*(4 m)^2 + 8 m*(2*3.14*4m) =401.92 m^2

6 0

3 years ago