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TEA [102]
2 years ago
11

Using the formula V=lwh, find w when l=10, h=20 and v=2000

Mathematics
2 answers:
Paha777 [63]2 years ago
8 0
The answer to the question is w= 10
rosijanka [135]2 years ago
5 0

Answer:

w = 10

Step-by-step explanation:

Given

V = lwh ← substitute the given values

2000 = 10 × w × 20, that is

2000 = 200w ( divide both sides by 200 )

10 = w

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The distribution of the number of words in text messages between employees at a large company is skewed right
kaheart [24]

The probability the sample mean is more than 10 words for a random sample of 39 messages is 2.12%

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The z score is given by:

z = (raw score - mean) / (standard deviation / √sample size)

Given mean of 8.6 words and a standard deviation of 4.3 words. If a random sample of 39 messages, hence, for x > 10:

z = (10 - 8.6) / (4.3 / √39) = 2.03

P(x > 10) = P(z > 2.03) = 1 - P(z < 2.03) = 1 - 0.9788 = 0.0212

The probability the sample mean is more than 10 words for a random sample of 39 messages is 2.12%

Find out more on equation at: brainly.com/question/2972832

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8 0
1 year ago
What is the surface area of the cylinder with the height of 6ft and the radius of 6ft. round your answer to the nearest thousand
Damm [24]
2.7 is the answer you should get help
7 0
2 years ago
Which of the following comparisons is False
Verizon [17]
A graph shows the first comparison is true, and the C temperature is cooler than the F temperature for the remaining comparisons.

The comparison that is FALSE is ...
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3 years ago
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Vladimir [108]
It's 6.9. Just do the circumference divided by pi
6 0
3 years ago
Read 2 more answers
On the average, a grocer sells three of a certain article per week. How many of these should he have in stock so that the chance
olga2289 [7]

Answer:

7

Step-by-step explanation:

This is a Poisson distribution problem with the formula;

P(x;μ) = (e^(-μ)) × (μ^(x))/x!

We are told that the grocer sells three of a certain article per week. Thus;

μ = 3

Now, we want to find out How many of these should he have in stock so that the chance of his running out within a week is less than 0.01.

This means;

P(X > k) < 0.01

This can be rewritten as;

P(X ≤ k) < 0.99

Let's try x = 8

P(8;3) = (e^(-3)) × (3^(8))/8!

P(8;3) = 0.008

But; P(X ≤ 8) = 1 - 0.008 = 0.992

This is more than 0.99 and thus is not the answer

Let's try x = 7

P(7;3) = (e^(-3)) × (3^(7))/7!

P(7;3) = 0.022

But; P(X ≤ 7) = 1 - 0.022 = 0.978

Thus is less than 0.99.

Thus, stock should be 7

5 0
2 years ago
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