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Margaret [11]
4 years ago
10

An angle measuring 468 n degrees Is in standard position. For which value of N will the terminal side fall on the axis

Mathematics
1 answer:
Fudgin [204]4 years ago
6 0
N=5 I think, tell me if it is correct
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Ussions
ankoles [38]

Answer:

All points on line CD are equidistant from A and B

Step-by-step explanation:

Given that point A is the center of circle A and point B is the center of circle B,  and the circumference of circle A passes through the center of circle B which is point B and vice versa.

Therefore we have;

The radius of circle A = The radius of circle B

Which gives;

The distance of the point C to the center A is equal to the distance of the point C to the center B

Similarly, the distance of the point D to the center A is equal to the distance of the point D to the center B

So also the distances of all points on the line from the center A  is equal to the distances of all points on the line from the center B.

6 0
3 years ago
Can I get some help with this one? please? (UwU)
Mama L [17]

Answer:

L to G

d

e

b

c

a

Step-by-step explanation:

Hope this helps :)

8 0
3 years ago
Read 2 more answers
What is the range for this set of data? 38, 17, 55, 40 02 38 39 O 72​
34kurt

Answer:

38

Step-by-step explanation:

The range is the difference between the highest value and the lowest value. Here the highest value is 55 and the lowest 17. Therefore, the range is take away 17 from 55 which equals to 38

8 0
3 years ago
Solve for x: 10x – 3 + x < 30
Gala2k [10]

Answer:

The correct answer would be the last one; x < 3.

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

11x - 3 < 30

Step 2: Add 3 to both sides.

11x - 3 + 3 < 30 + 3

11x < 33

Step 3L Divide both sides by 11.

11x/11 < 33/11

Therefor, the correct answer would be the last one: x < 3

Hope this helps!

7 0
3 years ago
Read 2 more answers
Solve the equation |x-2|-3=0 first by finding the zeros of<br> y=|x-2|-3 and then algebraically.
tino4ka555 [31]

Answer:

The solution of given equation are -1 and 5.

Step-by-step explanation:

The given equation is

|x-2|-3=0

We need to solve the above equation by finding the zeros of

y=|x-2|-3

The vertex form of an absolute function is

y=a|x-h|+k

where, a is constant and (h,k) is vertex.

Here, h=2, k=-3. So vertex of the function is (2,-3).

The table of values is

   x           y

   0         -1

   2         -3

   4         -1

Plot these points on a coordinate plane and draw a V-shaped curve with vertex at (2,-3).

From the given graph it is clear that the graph intersect x-axis at -1 and 5. So, zeroes of the function y=|x-2|-3 are -1 and 5.

Therefore the solution of given equation are -1 and 5.

Now solve the given equation algebraically.

|x-2|-3=0

Add 3 on both sides.

|x-2|=3

x-2=\pm 3

Add 2 on both sides.

x=\pm 3+2

x=3+2 and x=-3+2

x=5 and x=-1

Therefore the solution of given equation are -1 and 5.

3 0
4 years ago
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