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Akimi4 [234]
3 years ago
10

Convert the equation to y=mxtb 2x-3y=-6 please show the steps .

Mathematics
1 answer:
stellarik [79]3 years ago
7 0
You subtract the x from both sides of the equation so it will then be -3y = -2x - 6. You then divide each number by -3, -3y divided by -3, -2x divided by -3, and the - 6 divided by negative 3. It would equal y = 2/3x + 2
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Which of the following functions is graphed above?
Varvara68 [4.7K]
A is the answer because u have to shift up two units and move it right 8 units
8 0
3 years ago
Check the true statements below:
valentinak56 [21]

Answer:

a) False

b) False

c) True

d) False

e) False

Step-by-step explanation:

a. A single vector by itself is linearly dependent. False

If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.

b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False

A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.

c. The columns of an invertible n × n matrix form a basis for Rⁿ. True

If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.

d.  In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False

Row operations can not affect linear dependence among the columns of a matrix.

e. A basis is a spanning set that is as large as possible. False

A basis is not a large spanning set. A basis is the smallest spanning set.

3 0
3 years ago
You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. Find the probability that t
icang [17]

Answer:

The probability that the first card is a Heart and the second card is a Spade is 0.064.

Step-by-step explanation:

A standard deck of 52 cards is shuffled and two cards are drawn without replacement.

The denominations of the cards are as follows:

Spades (S) = 13

Hearts (H) = 13

Diamonds (D) = 13

Clubs (C) = 13

Compute the probability of selecting a Heart first as follows:

P(H)=\frac{13}{52}=0.25

Compute the probability of selecting a Spade second as follows:

P(S)=\frac{13}{51}=0.255

Since the two cards are selected without replacement the second draw is independent of the other.

Then the probability that the first card is a Heart and the second card is a Spade is:

P(1st\  H\cap 2nd\ S)=P(H)\times P(S)

                            =0.25\times 0.255\\=0.06375\\\approx 0.064

Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.

4 0
3 years ago
At the local pet store, zebra fish cost $1.85 each and neon tetras cost $2.10 each. If Yumi bought 11 fish for a total cost of $
Amanda [17]

Answer: C. 6 zebra fish, 5 neon tetras. Is $21.60

Step-by-step explanation:

1.85 • 6 = 11.10

2.10 • 5 = 10.50

11.10 + 10.50 = 21.60

$21.60

5 0
2 years ago
Evaluate a+b when a=5/6 and b=3 1/4
NemiM [27]

Answer:

4 1/12

Step-by-step explanation:

a = 5/6        b = 3 1/4 = 13/4

To add 5/6 + 13/4, we have to make the denominators the same:

20/24 + 78/24 = 98/24
To make it back to a mixed fraction:

4 2/24
4 1/12

4 0
2 years ago
Read 2 more answers
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