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Lorico [155]
3 years ago
8

Brainiest to who ever answers first

Mathematics
1 answer:
Marina86 [1]3 years ago
4 0
The answer is A because 3 and 18 both have 3 in common and 5 and 25 both have 5 in common!
You might be interested in
A Movie theater sold 5 times as many children's tickets as adult tickets to an afternoon show. If 132 tickets were sold in all,
Vikentia [17]
22x5=110
110+22=132
so if they sold 22 adult tickets 5 times that many is 110. they sold 110 children tickets, plus the 22 adult tickets equals the total of 132 tickets. So the answer is 110
7 0
3 years ago
Can somebody please explain the question and the answer I’m so, so lost in this unit.
Svetlanka [38]

Answer:

Undefined

Step-by-step explanation:

1. In order to even begin to answer this question, we'll need to find the definition of a few terms:

Coefficient: A constant quantity placed before a variable in an equation.

  • ex: the <em>3 </em>in the expression 3x^3 is the coefficient.

The expansion of an equation is the unfactored version of an equation.

  • ex: x^2 +2x + 1 is the expansion of (x + 1)^2

2. Based on these definitions, the question is asking:

"What number is in front of of x^3 in the expanded version of (6x + 5y)^4?"

It still sounds super confusing, but at least its comprehensible.

3. Now that we know what we're being asked for, we can begin to solve... but how? Expanding (6x + 5y)^4 seems like it would take forever right?

This is when it gets complicated. You'll to have a couple concepts in your mind:

  • The equation nC_r=n!/r!*(n!-r!). This is called the Combination Formula
  • Pascal's Triangle. I recommend finding an image of it.

<em>If what I'm doing right now seems confusing, look up how to, "Find the Coefficient of an Expansion." I checked and there are videos on this.</em>

4. Here is the order of how we solve this problem from this point forward:

  1. Define our variables
  2. Translate our variables into the format that our question is asking for.
  3. Plug the translated variable into the Combination Formula.
  4. Solve

5. We are given two different variables to expand. (6x) and (5y). The question is asking for the coefficient in front of x^3, so our format is (6x)^3(5y)^0. The 5y should still be shown although its exponent is 0.

<em>I'm going to have to again stress looking for videos on what exactly I'm doing. I'm sorry that I can't properly teach Combinations. From this point on you may have trouble understanding what's going on.</em>

Math:

  • (6x)^3(5y)^0
  • 4C_0(6x)^3(5y)^0

Change 4C_0 into the format of the Combination Formula

  • 4C_0 = 4!/ 4! - (4! - 0!)

Now plug this back into our equation

  • = (4!/(4! - 4!)) (6x)^3(5y)^0
  • = (4!/0) (6x)^3
  • undefined

There is no term containing x^3 based on the fact that 4C_0 is undefined.

I hope that you can figure out Combinations. I remember learning about them, but it is a very conceptual concept. Once you do figure out how they work though, they become very easy to use. Good luck on your math.

6 0
3 years ago
Jason begins at the start of a path and rides his bike 11 and a half miles on the path the path is 12 and a 1/4 miles long whats
Paladinen [302]
We just need to subtract the total miles he has already rode from the total miles of the path.
12.25-11.5
0.75
So, he must bike 3/4 miles to reach the end.
4 0
4 years ago
Given are the functions f(x) = x ^ 2 and g(x) = (x - 2) ^ 2 + 1 How can the graph of g(x) be obtained from the graph of f(x) ?
Levart [38]

Answer:

c because it's the opposite

5 0
3 years ago
&gt;, &lt; or =<br> 13<br> 27<br> To 5/9
Leto [7]

Answer:

13 < 27 > to 5/9

Step-by-step explanation:

Any fraction that isn't mixed cannot be larger than a whole number. 13 is lesser than 27.

6 0
4 years ago
Read 2 more answers
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