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8090 [49]
4 years ago
5

Which of the following is NOT a property of the F​ distribution? Choose the correct answer below. A. Values in the F distributio

n cannot be negative. B. The exact shape of the F distribution depends on the two different degrees of freedom. C. The F distribution is not symmetric. D. The F distribution is bell shaped.
Mathematics
1 answer:
Nitella [24]4 years ago
4 0

Answer:

The correct answer is D..

Step-by-step explanation:

The F-distribution, or Fisher-Snedecor distribution is a well known probability distribution with many applications in Statistics. The graph of its probability density function has several shapes depending of the parameters. Recall that the F-distribution has two free parameters. In the attached graph (https://en.wikipedia.org/wiki/F-distribution#/media/File:F-distribution_pdf.svg) it is shown different shapes of the F-distribution in terms of different values of the parameters.  

Download pdf
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Hunter sells some books to 4 of his friends. He earns $53.00. If each friend spent the same amount of money, how much money did
labwork [276]

Step-by-step explanation:

Divide $53.00 by 4 to represent how much each friend has paid for.

\frac{53}{4} = \$ 13.25

Each friend has paid $13.25 to Hunter.

3 0
3 years ago
Helpppppppppppppppp please y’all
max2010maxim [7]

\sf{3. \ \ Given : \dfrac{2}{3} - \dfrac{5}{4} + \dfrac{7}{2}}

Let us solve the first two fractions : The LCM of 3 and 4 is 12

\sf{\implies \dfrac{4(2) - 5(3)}{12} + \dfrac{7}{2}}

\sf{\implies \dfrac{8 - 15}{12} + \dfrac{7}{2}}

\sf{\implies \dfrac{-7}{12} + \dfrac{7}{2}}

LCM of 2 and 12 is 12

\sf{\implies \dfrac{-7 + 7(6) }{12}}

\sf{\implies \dfrac{-7 + 42}{12}}

\sf{\implies \dfrac{35}{12}}

\sf{\implies 2 +\dfrac{11}{12}}

\sf{\implies 2 \dfrac{11}{12}}

---------------------------------------------------------------------------------------

\sf{4. \ \ Given : \dfrac{(2 - 7)^2 + 5}{3}}

\sf{\implies \dfrac{(-5)^2 + 5}{3}}

\sf{\implies \dfrac{25 + 5}{3}}

\sf{\implies \dfrac{30}{3}}

\sf{\implies 10}

7 0
3 years ago
Read 2 more answers
If g is the midpoint of FH find Fg
Tasya [4]

If G is the midpoint of FH find FG

fg=11x-7 gh= 3x+9

4 0
3 years ago
Pentagon jklmn is translated five units up. what is the name of the image after translation?
mrs_skeptik [129]

There will not be any specific name given to that image after translation

<u>Step-by-step explanation:</u>

  • Whatever may be the transformation, either it may be rotation, reflection or translation, the size or shape of the image will not change no matter what the condition is and hence the name of that image will also not change and remains constant.
  • Thus we can conclude that the name of the image will always tend to remain constant and not changes.

4 0
3 years ago
Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x
Svet_ta [14]

Answer:

A^{'} = {1,3,5,7,9,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = {1,2,3,4,5}

D^{'} = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set  C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

A^{'} = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

A^{'} = {1,3,5,7,9,....}

B^{'} = U-B =  {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

C^{'} = {1,2,3,4,5}

D^{'} = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

D^{'} = {10,11,12,13,14,15,......}

8 0
3 years ago
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