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Alja [10]
4 years ago
15

Which shows the following expression after the negative exponents have been eliminated?

Mathematics
2 answers:
Vikentia [17]4 years ago
8 0

Given expression: \frac{-3a^{-2}b^3}{15a^{-7}b^{-1}\:}.

We need to find the simplified expression after eliminating negative exponents.

<em>According to rules of negative exponents, the negative exponents terms get switch from top to bottom and bottom to top by making exponent positive.</em>

Therefore, a^{-2} would go in the bottom, and a^{-7}b^{-1} would go on the top by making exponents positive.

So, it would become :\frac{-3a^{7}b^3b^{1}}{15a^2}.

<h3>So, the correct option is B. \frac{-3a^{7}b^3b^{1}}{15a^2}.</h3>
Nataly_w [17]4 years ago
5 0
The answer is B for those needing it. 
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Answer:c

Step-by-step explanation:

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3 years ago
A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard d
omeli [17]

Answer:

anything below 136.5 or above 155.5

Step-by-step explanation:

the critical value from a Z distribution for the 99% confidence level is 2.576

so we just need to compute

146 + 2.576(34/sqrt(85))

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146 + 2.576(34/sqrt(85))

8 0
4 years ago
Read 2 more answers
SEE QUESTION IN IMAGE
Pavel [41]

Answer:

<h3>23</h3>

<u>Data is:</u>

  • 5, 6, 7

<u>Mean:</u>

  • (5 + 6 + 7)/3 = 6

<u>Standard deviation:</u>

  • σ = \sqrt{((5 - 6)^2+(6-6)^2+(7-6)^2)/3} = \sqrt{2/3}

Correct choice is d

<h3>24</h3>

<u>Data is:</u>

  • -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5

<u>Mean:</u>

  • (-5 -4 - 3 - 2 - 1 + 0 + 1 + 2 + 3 + 4 + 5)/11 = 0

<u>Standard deviation:</u>

  • σ = \sqrt{((-5)^2+(-4)^2+(-3)^2+(-2)^2+(-1)^2+0^2+1^2+2^2+3^2+4^2+5^2)/11} =  \sqrt{10}

Correct choice is d

<h3>25</h3>

<u>Data is:</u>

  • 3, 4, 5, 6, 7

<u>Mean is:</u>

  • 5

<u>Standard deviation:</u>

  • σ = \sqrt{((3-5)^2+(4-5)^2+(5-5)^2+(6-5)^2+(7-5)^2)/5} =  \sqrt{2} ≈ 1.4

Correct choice is d

5 0
3 years ago
Is 17 heartbeats in 15 seconds a unit rate? Why or why not?
g100num [7]
No, because it is not per second. You would have to simplify to per one second for it to be a unit rate. Hope it helps! :)
8 0
3 years ago
A circle's radius that has an initial radius of 0 cm is increasing at a constant rate of 5 cm per second.
djyliett [7]

Answer:

a) r(t)=5t

b) A=\pi\cdot r^2

c) A=\pi\cdot (5t)^2

d) A=25\pi  t^2

Step-by-step explanation:

We know that the circle is increasing its radio from an initial state of r=0 cm, at a rate of 5 cm/s.

This can be expressed as:

r(0)=0\\\\dr/dt=5\\\\r(t)=r(0)+dr/dt\cdot t=0+5t\\\\r(t)=5t

a) Radius of the circle, r (in cm), in terms of the number of seconds, t since the circle started growing:

r(t)=5t

b) Area of the circle, A (in square cm), in terms of the circle's radius, r (in cm):

A=\pi\cdot r^2

c) Circle's area, A (in square cm), in terms of the number of seconds, t, since the circle started growing:

A=\pi\cdot r^2\\\\A=\pi\cdot (5t)^2

d) Expanded form for the area A:

A=\pi\cdot (5t)^2=25\pi\cdot t^2

3 0
3 years ago
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