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3 years ago

How is the number of vertices related to the number of sides of the polygon and to the type of polygon? Give two examples.

1 answer:

8 0

Well,

Take a triangle. It has three vertices and three sides. The three vertices dictate that there will be three sides. The same rule applies for a quadrilateral (four vertices and sides), a pentagon (five vertices and sides), etc. So the number of vertices in a polygon is equal to the number of sides in the same polygon.

Taking this a step further, since the number of vertices are equal to the number of sides, we can conclude that a polygon with three vertices is a triangle, a polygon with four vertices is a quadrilateral, a polygon with five vertices is a pentagon, etc.

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Answer:

Step-by-step explanation:

3:2 means 3/2 or 3÷2

but its better to leave it as

3/2

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3 years ago

I need the help on this

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Step-by-step explanation:

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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

$F = \dfrac{9}{6^x}$

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

$W = \int\limits^{x_2}_{x_1} {F(x)} \, dx$

with $x_1$ and $x_2$ the initial and final displacements respectively.

From the question, $x_1 =0$ and $x_2 = 12$ .

Then

$W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx$

Evaluating the indefinite integral,

$\int\limits \dfrac{9}{6^x} \, dx =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx$

From the rules of integration,

$\int\limits a^x\, dx = \dfrac{a^x}{\ln a}$

$9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x$

Returning the limits,

$\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}$

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3 years ago

Data was collected on the number of pets and the height of a random group of students. Identify the correlation you would expect

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No correlation
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3 years ago

How to turn 20/10 into a mixed number

Lady_Fox [76]

$\frac{20}{10}$ cannot be changed to a mixed number. 10 could divide both numerator and denominator. And you get 2.

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4 years ago

Read 2 more answers