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grigory [225]
3 years ago
14

How can I find the area of a rectangle with a rectangle the size of w- 2in and l- 5 in. I need two ways and i need a lot of easy

explaining because I need to draw how I did it.
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
6 0
Here's one way: A=WxL So in this case, it's 2x5 You would draw the rectangle, label one side 2 in. and the other 5 in. Draw an arrow from each no./side and put x underneath the line so that its 2 —x— 5 (2, line, x, line, 5. With x under line)
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-4(y-2)=12<br> what is the answer
AysviL [449]

Answer:

y=−1

Step-by-step explanation:

Let's solve your equation step-by-step.

−4(y−2)=12

Step 1: Simplify both sides of the equation.

−4(y−2)=12

(−4)(y)+(−4)(−2)=12(Distribute)

−4y+8=12

Step 2: Subtract 8 from both sides.

−4y+8−8=12−8

−4y=4

Step 3: Divide both sides by -4.

−4y

−4

=

4

−4

y=−1

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RoseWind [281]
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8 0
2 years ago
Leo has a lock box with a volume of 312 cubic inches. The box is 4 inches high and 13 inches long. What is the width of the box?
natima [27]

Answer:

6in

Step-by-step explanation:

Given data

Volume of the lockbox= 312 cubic inches

Height= 4in

Length= 13in

Width= ???

The expression for the volume of box is

V= L*W*H

substitute

312=13*W*4

312=52W

W= 312/52

W=6 in

Hence the width is 6in

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