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grigory [225]
3 years ago
14

How can I find the area of a rectangle with a rectangle the size of w- 2in and l- 5 in. I need two ways and i need a lot of easy

explaining because I need to draw how I did it.
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
6 0
Here's one way: A=WxL So in this case, it's 2x5 You would draw the rectangle, label one side 2 in. and the other 5 in. Draw an arrow from each no./side and put x underneath the line so that its 2 —x— 5 (2, line, x, line, 5. With x under line)
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Which value of p makes the equation 18+ 2 (3p – 8) = –37 true?
Volgvan

Answer:

p = -6.5

Step-by-step explanation:

<u>Given:</u>

  • 18+ 2 (3p – 8) = –37

<u>Solving for p:</u>

  • 18+ 2 (3p – 8) = –37
  • 18 + 6p - 16 = -37
  • 6p + 2 = -37
  • 6p = -37 - 2
  • 6p = -39
  • p = -39/6
  • p = -6.5

Option 2 is correct in the list

3 0
3 years ago
Janelle subtracts -4 from a number the result is 2 what is the number​
Gre4nikov [31]

Answer:

6

Step-by-step explanation:

Unknown number = x

So,

x - 4 = 2 (add 4 to both sides)

x - 4 + 4 = 2 + 4

x = 6

6 0
3 years ago
Read 2 more answers
Please help I will give Brainliest please!
WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but x \ne 0</h3>

To write this in interval notation, we can say (-\infty, 0) \cup (0, \infty) which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say (-\infty, \infty) which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation x = \pm 4

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer:  Oblique asymptote is y = 3x</h3>
5 0
3 years ago
In the diagram, BC¯¯¯¯¯∥DE¯¯¯¯¯ . What is CE ? Enter your answer in the box. ft
Marizza181 [45]

The segments AE, EC, AD and DB are in proportion.

Therefore we have the equation:

\dfrac{CE}{BD}=\dfrac{AE}{AD}

AE = 4ft, AD = 8ft and BD = 2ft. Substitute:

\dfrac{CE}{2}=\dfrac{\not4^1}{\not8_2}      <em>multiply both sides by 2</em>

CE=\dfrac{1}{\not2_1}\cdot\not2^1\\\\\boxed{CE=1\ ft}

4 0
4 years ago
If I add 35 mL of water to 225 mL of a 0.45 M NaOH solution, what will the molarity of the diluted solution be?
nata0808 [166]

Answer:

I don't know the answer what is the answer

3 0
3 years ago
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