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krok68 [10]
2 years ago
5

Please help I will give Brainliest please!

Mathematics
1 answer:
WITCHER [35]2 years ago
5 0

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but x \ne 0</h3>

To write this in interval notation, we can say (-\infty, 0) \cup (0, \infty) which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say (-\infty, \infty) which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation x = \pm 4

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer:  Oblique asymptote is y = 3x</h3>
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Answer:

Step-by-step explanation:

h=11.4 in

r=5.1 in

v=3.14*r^2*(h/3)

V=3.14*5.1^2*(11.4/3)=3.14*26.01*3.8=310.35

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2 years ago
Simplify: 18-|8+3(2+2)-4|
NeX [460]

Answer:

2

Step-by-step explanation:

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3 years ago
PLEASE I NEED HELP
notka56 [123]

You would transform 5x + 2x into the same term with the associative property, adding like terms. If you subsitute the different values into the expressions you notice that both have a rate of change of 7 like an arithmetic sequence. To see if any value will make the two expressions equal you make them equal to each other.

5x + 2x = 7x -1

7x = 7x - 1

0 = -1

No they will never have be a solution  to both expressions to make them equal because they're parallel to each other.

7 0
3 years ago
Vaughn Manufacturing has three product lines. Its only unprofitable line is Corn Nuts, the results of which appear below for 201
elena-14-01-66 [18.8K]

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3 years ago
9th question help ?!
Daniel [21]
Hey there! :)

You have to find the area of all of them and add it together.

Formulas:

Area of a square: l · w
Area of a triangle: (b · h) ÷ 2

Square - 

l = 3
w = 3

3 × 3 = 9

Triangle - 

b = 3
h = 3

(3 × 3) ÷ 2
    9  ÷    2   = 4.5

There are 4 triangles

4.5 × 4 = 18

9 + 18 = 27

The surface area ⇒ 27 cm²



5 0
3 years ago
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