Answer:
B
Step-by-step explanation:
each time she sells 2 cards she gets $9 right?
so counting by 2's is the best route to go on and the only answer that displays that is answer B
For the answer to the questions above,
A) Parrots are following a Geometric Progression of 15% increase.
20(1.15), 20(1.15)², 20(1.15)³,
Function = 20(1.15)^n Where n is at the end of year, n =1, 2, 3, ..
Snakes are increasing by 4.
28, 32, 36,....
Function = 24 + 4n n = number of end year, n =1, 2, 3,...
<span>B) After 10 years: </span>
Parrot = 20(1.15)¹⁰ = 80.91115471
Snakes = 24 + 4(10) = 64
<span>C) After what time they are the same: </span>
We use trial and error:
Test: n 20(1.15^n) (24 + 4n)
1 23 28
2 26.45 32
<span> 3 30.41 36 </span>
4 34.98 40
5 40.23 44
6 46.26 48
7 53.20 52
8 61.18 56
9 70.36 60
After year 7, the Parrots increases far more.
<span>At year 7 they are roughly the same.</span>
Answer:
$34
Step-by-step explanation:
I'd work backwards.
For the third book, she paid all her remaining money. The problem says she paid "1/2 her leftover money + $3". This means that: (let m = money used to buy book 3)
m = 1/2m + 3
1/2m = 3
m = 6
For the second book: (let n = money before book 2)
n - m (money left after book 2) = 1/2n + 2
1/2n +2 is money used up for book, which is the same as n-m.
n = 1/2n + 2 + m
1/2n = 2 + m = 2 + 6
1/2n =8
n = 16
For the first book, she spent 1/2 her money + 1. If o = money before book 1 (or the whole allowance):
o - n = 1/2o + 1
o = 1/2o + n + 1 = 1/2o + 16 + 1
1/2o = 17
o = 34
Check!
Spent 17 (half 34) + 1 on book 1
16 left
Spent 8 (half 16) +2 on book 2
6 left
Spent 3 (half 6) + 3 on book 3
0 left
The area of the square:
where "a" is a length of side.
Therefore:
Answer: (10,9) is the correct answer.
