Let us name the players A,Dave,Zack,Paul,E and F
For the first position there are two candidades ( Zack / Paul )
For the second position there is only one candidate i.e. Dave
For the third place there will be 4 candidates (out of Zack and Paul - 1 as one of them is already taken for the first position and A, E and F total-4)
For the fourth place there will be 3 candidates ( out of the four available candidates in the 3rd place, one will be taken up for 3rd place )
For the fifth place there will be 2 candidates
Finally, for the last place there will be only one candidate left.
On multiplying the no. of available cadidates, we get 2 * 1 * 4 * 3 * 2 * 1 = 48 i.e. option (A)
Please mention minor spelling mistakes
For the second question:
Let the no of dotted marbles be 'x' and no of striped marbles be 'y'
then the equation will become as follows
(y+6)/x = 3
and
(x+6)/y = (2/3)
On solving the equations, we will get x = 10 and y = 24
Total balls = 10+24+6 = 40 (option E)
Answer 3 will be ) For the first edge, he can choose 3 paths
For the second edge he can choose 2 paths for each path of its first edge's path
For the third , he is bounded to move on the paths created by the first and the second edges hence 1 path for each path created by the first and the second edge together
It will be multiplication of all the possibilities of the paths of the three edges differently.........
i.e. 3 * 2 * 1 = 6
1/3 has the greatest value
Answer:
40
Step-by-step explanation:
x = (180-100)/2 = 40
Four scarves and six hats is $52.00
<span>4s+6h=52 </span>
<span>two hats is $1.00 more than the cost of one scarf. </span>
<span>2h=1s+1 </span>
<span>2h=s+1 </span>
<span>s=2h-1 </span>
<span>substitute for s </span>
<span>4s+6h=52 </span>
<span>4(2h-1)+6h=52 </span>
<span>8h-4+6h=52 </span>
<span>14h=56 </span>
<span>h=4 </span>
<span>s=2h-1 </span>
<span>s=8-1 </span>
<span>s=7 </span>
<span>a scarf cost $7 </span>
<span>a hat cost $4</span>
