Number 1 would the last option, but I’m not sure about number 2
N=2
The smallest value of f(x) on [0, π/2] is 2, which occurs at x = 0. The smallest value of f(x) on [π/2, π] is also 0, which occurs at x = π. So the lower sum is (π/2)(2 + 2) = 2π
The largest value of f(x) on [0, π/2] is 3, which occurs at x = π/2. This is also true for the interval [π/2, π]. So the upper sum is (π/2)(3 + 3) = 3π
n = 4:
f '(x) = cos(x), which is positive for [0, π/2) and negative for (π/2, π]. This tells us that f is an increasing function on [0, π/2) and a decreasing function on (π/2, π]. So for the lower sum you will always evaluate f at the left endpoint of the subinterval if that subinterval lies in [0, π/2], and at the right endpoint of the subinterval if it lies in [π/2, π]
Thus, the lower sum for n = 4 is
(π/4)(f(0) + f(π/4) + f(3π/4) + f(π))
and the upper sum is
(π/4)(f(π/4) + f(π/2) + f(π/2) + f(3π/4)).
the lower sum for n=8 is
(π/8)(f(0)+f(π/8)+f(π/4)+f(3π/8)+f(5π/8...
and the upper sum is
(π/8)(f(π/8)+f(π/4)+f(3π/8)+f(π/2)+f(π/...
Arc AC would be 90 degrees because the line is bisects the straight line (180 Degrees)
Answer: 90 Degrees
Answer: Translate triangle ABC so that point B lies on point D to confirm ∠B ≅ ∠D.
Step-by-step explanation: Since we already know that angle A is congruent to itself by the reflexive property, all we need is another pair of corresponding angles to be congruent according to the AA (angle-angle) similarity postulate. This postulate states that; If two corresponding angles of two or more triangles are congruent, the triangles are similar. So when we translate triangle ABC so that point ∠B lies on ∠D, we prove that these two angles are congruent.
I also got it right on the test. So... yeah.
hope this helps dood.
Answer:
Commutative property
Step-by-step explanation:
addition is commutative for example 2+3=3+2
multiplication is also commutative 3*2=2×3