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2 years ago

Mrs. Williams estimates that she will spend $65 on

Mathematics

1 answer:

galina1969 [7]2 years ago

7 0

Answer:

Estimates: $65

Actually: $73

65 / 73

= 0.9 (round to nearest tenth)

I hope this helps, I may be wrong. Somebody can correct me if I am wrong. :)

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anygoal [31]

Answer:

x=2, y=-2

Step-by-step explanation:

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2 years ago

Can x and y intercepts be in decimals or fractions?

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3 years ago

Read 2 more answers

Please Help me ASAP i need to turn it in, in like 10 min. Please answer the questions in the screenshot ill give u 20 points Tha

Delvig [45]

Answer:

for #1 its the 1st and 4th box

for # 2 it's 13.5 and 20.25

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3 years ago

Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.

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3 years ago