Volume of a rectangular box = length x width x height<span> From the problem statement, length = 60 - 2x width = 10 - 2x height = x</span>
<span> where x is the height of the box or the side of the equal squares from each corner and turning up the sides V = (60-2x) (10-2x) (x) V = (60 - 2x) (10x - 2x^2) V = 600x - 120x^2 -20x^2 + 4x^3 V = 4x^3 - 100x^2 + 600x To maximize the volume, we differentiate the expression of the volume and equate it to zero. V = </span>4x^3 - 100x^2 + 600x<span> dV/dx = 12x^2 - 200x + 600 12x^2 - 200x + 600 = 0</span>
2
1+3
1+32+2