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Olenka [21]
3 years ago
8

the brightness of the illumination of an object varies inversely as the square of the distance from the object to the source of

light. how far from the bulb does an object receive four times as much illumination as it does when it is 8 m from the bulb
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
3 0
I=k/d^2

4=k/d^2 and 1=k/64  so if we divide the first by the second we get:

4/1=(k/d^2)/(k/64)

4=(k/d^2)*(64/k)

4=64/d^2

d^2=64/4

d^2=16

d=4 meters


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Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

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To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

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