the brightness of the illumination of an object varies inversely as the square of the distance from the object to the source of
light. how far from the bulb does an object receive four times as much illumination as it does when it is 8 m from the bulb
1 answer:
I=k/d^2
4=k/d^2 and 1=k/64 so if we divide the first by the second we get:
4/1=(k/d^2)/(k/64)
4=(k/d^2)*(64/k)
4=64/d^2
d^2=64/4
d^2=16
d=4 meters
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Answer:
sorry can't understand the language
3 sqrt (6) should be correct
The lower end of the range is
42.670 - 0.002 = 42.668 mm
The upper end of the range is
42.670 + 0.002 = 42.672 mm
The range of acceptable values is 42.668 mm to 42.672 mm.
-2
----
5
Because perpendicular is the opposite and the opposite of -5/2 is -2/5
