Answer:
490.1
Step-by-step explanation:
A=2πrh+2πr2=2·π·6·7+2·π·62≈490.08845
<h3>
Answer: c = 900</h3>
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Explanation:
We are dividing c by 15 to get 60. To isolate c, we undo what is happening to the variable. So we multiply both sides by 15
c/15 = 60
15*(c/15) = 15*60 ... multiply both sides by 15
c = 900
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As a check,
c/15 = 60
900/15 = 60 ... replace every copy of c with 900
60 = 60 .... we get a true equation
Since the last equation is true, this confirms the solution c = 900.
Answer:
In order to find this answer, you will need to be able to make an inequality.
Step 1: Sophia makes $40 so start with that. 40
Step 2: Sophia also makes $5 per every outfit that she sells, so add that plus your variable (n). 40+5n
Step 3: Determine if Sophia wants to make more, equal to or more, less, or less than or equal to than what she wants to make per day. 40+5n *draw a greater than or equal to sign.
Step 4: Sophia wants to make more than or equal to what she makes per day. You will need to find what she wants to make more than. In this she wants to make more than or equal to $70.
Equation: 40+5n *greater than or equal to sign* $70
Step-by-step explanation:
Answer:
38 1/4
Step-by-step explanation:
First I convereted 8 1/2 and 4 1/2 to fractions, because it is easier for me, which gives you
8.5*4.5
Multiplying this out you get 38.25, which is equal to 38 1/4.
If you do it by fractions you convert them to inproper fractions.
8 1/2= 17/2
4 1/2= 9/2
You then multiply and get 153/4
When you divide 153 by 4 you get 38 1/4
This equation has some nested grouping symbols on the left-hand side. As usual, I'll simplify from the inside out. I'll start by inserting the "understood" 1 in front of that innermost set of parentheses:
3 + 2[4x – (4 + 3x)] = –1
3 + 2[4x – 1(4 + 3x)] = –1
3 + 2[4x – 1(4) – 1(3x)] = –1
3 + 2[4x – 4 – 3x] = –1
3 + 2[1x – 4] = –1
3 + 2[1x] + 2[–4] = –1
3 + 2x – 8 = –1
2x + 3 – 8 = –1
2x – 5 = –1
2x – 5 + 5 = –1 + 5
2x = 4
x = 2
It is not required that you write out this many steps; once you get comfortable with the process, you'll probably do a lot of this in your head. But until you reach that comfort zone, you should write things out at least this clearly and completely.
Always remember, by the way, that you can check your answers in "solving" problems by plugging the numerical answer back in to the original equation. In this case, the variable is only in terms on the left-hand side (LHS) of the equation; my "check" (that is, my evaluation at the solution value) looks like this:
LHS: 3 + 2[4x – (4 + 3x)]:
3 + 2[4(2) – (4 + 3(2))]
3 + 2[8 – (4 + 6)]
3 + 2[8 – (10)]
3 + 2[–2]
3 – 4
–1
Since this is what I was supposed to get for the right-hand side (that is, I've shown that the LHS is equal to the RHS), my solution value was correct.
