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Lady bird [3.3K]
3 years ago
15

Scenario: Does the age at which babies learn to crawl depend on the time of the year that the babies were born? Data were collec

ted from parents who brought their babies into the University of Denver’s Infant Study Center to participate in one of a number of experiments between 1988 and 1991. Parents reported the birth month and the age in which their child first began to crawl. The resulting data were grouped by month of birth: January, May, and September.
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

The age for when babies learn to crawl is different for Januar,May, and September.. so I guess yes?

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Answer:

1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30    

1.1+2.02\frac{4.9}{\sqrt{50}}=2.50    

So on this case the 90% confidence interval would be given by (-0.30;2.50)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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\bar X=1.1 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=4.9 represent the sample standard deviation

n=51 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=51-1=50

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,50)".And we see that t_{\alpha/2}=2.02

Now we have everything in order to replace into formula (1):

1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30    

1.1+2.02\frac{4.9}{\sqrt{50}}=2.50    

So on this case the 90% confidence interval would be given by (-0.30;2.50)    

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