Answer:
2.486
3.1734
4.726
5.1350
6.canot see number in picture
7.864
8.54
Step-by-step explanation:
Answer:
(a) $3800
(b) (a) -- April to May
Step-by-step explanation:
<h3>(a)</h3>
The least amount is found at the lowest point on the graph. That point is in May. It is on the line between 3700 and 3900, so the amount is $3800.
The least donation amount is a month is $3800.
__
<h3>(b)</h3>
The greatest month-to-month decrease is found where the line on the graph has the steepest negative slope. There are two segments with negative slope:
- April - May (decrease of $500)
- June - July (decrease of $100)
The decrease from April to May is by far the largest of these two decreases.
The greatest decrease occurred April to May.
What do you mean angle 6?
Answer:
First term a₁ = 3/2 and common ratio r = 2
Step-by-step explanation:
We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96
Since common ratio is required so, the sequence is geometric sequence
The formula used is: 
We are given: third term = 6 i,e

Seventh term = 96

Dividing eq(2) and eq(3)

So, Common Ratio r = 2
Finding First term using eq(1)

So, First term a₁ = 3/2 and common ratio r = 2
Given:
Discount = 40%
Sales tax = 7%
To find:
The total cost of levi jeans with an original price of x.
Solution:
Let x be the original price of the jeans. Then the price after 40% discount is




The price after 7% of sales tax.




Therefore, the total cost of the levi jeans with an original price of x is represented by the expression 0.642x.