3 years ago

the length of a rectangle is 8 units greater than its width . find the dimensions when its area is 105 square units.

Mathematics

1 answer:

ASHA 777 [7]3 years ago

7 0

I hope this helps ;)

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Ilya [14]

Answer:

$\boxed{\sf sin\ C =\frac{40}{41}}$

Step-by-step explanation:

We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .

We know that the ratio of sine is perpendicular to hypontenuse .

$\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}$

Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,

$\sf\longrightarrow sinC =\dfrac{ p}{h}\\\\\sf\longrightarrow sin\ C =\dfrac{AB}{AC}$

Substitute the respective values ,

$\sf\longrightarrow \boxed{\blue{\sf sin\ C =\dfrac{40}{41}}}$

<u>Hence the required answer is 40/41.</u>

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