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devlian [24]
3 years ago
9

What is the scientific notation for 1,200,000,000

Mathematics
1 answer:
telo118 [61]3 years ago
8 0

Your answer should be:

1.2 x 10^{9}

Please mark brainliest :)

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Any one help me with this plsss and ni links plss!!
Bas_tet [7]

Answer:

6. D.

7.  F.

8. A.

9. B.

10. C.

Step-by-step explanation:

6.     9 + (12 - 10)

       12 - 10 = 2

        9 + 2 = 11

7.      (20 - 15) x 2

        20 - 15 = 5

         5 x 2 = 10

8.      10 ÷ 5 + 7

         10 ÷ 5 = 2

          2 + 7 = 9

9.        6 + 2 x 3

           2 x 3 = 6

           6 + 6 = 12

10.        (2 x 4) + 8

             2 x 4 = 8

             8 + 8 = 16

Let me know if this helps!

4 0
3 years ago
— 9y + 5у — 7y + Зу<br> I need help
Inessa05 [86]

Answer:

5gghbjfjhdjfjfifnrjfjfnfkfnf.jc79239nfkfnfjf

6 0
3 years ago
Steve drove for 8 1/2 hours at 72 miles per hour. How much distance did he travel?
Pie

Answer:

He traveled 612 miles in total.

Step-by-step explanation:

You simply multiply the mph he was going to how long he traveled for. This gives us 72x8.5 equaling 612.

7 0
3 years ago
Read 2 more answers
A stone is thrown downward with a velocity of 88 feet
Alchen [17]

Answer:

Step-by-step explanation:

B) the stone hits the water within the first 2 seconds. Because the stone drops at the speed of 88 feet/second, and 88 x 2 is 176. but the bridge is only 135 feet tall.

so,

88 feet/second

176 feet/2 seconds

135 feet means that it reached the river within 2 seconds. it reached the river in 1.545 seconds

7 0
2 years ago
Read 2 more answers
PLEASE HELP I WILL GIVE A LOT OF POINTS!
vazorg [7]

9514 1404 393

Answer:

  (2.27, 0.96)

Step-by-step explanation:

The orthocenter is the point of intersection of altitudes of the triangle. The equation for an altitude is the equation of a line through a vertex that is perpendicular to the opposite side.

For example, the line perpendicular to side AC can be found as ...

  (∆x, ∆y) = C-A = (3, -1) -(-4, 2) = (7, -3)

  ∆x(x -h) +∆y(y -k) = 0 . . . . perpendicular through point (h, k)

For side AC, we want the point to be B(4, 5), so the equation is ...

  7(x -4) -3(y -5) = 0

  7x -3y -13 = 0

Similarly, the altitude to side AB can be written as ...

  (∆x, ∆y) = B -A = (4, 5) -(-4, 2) = (8, 3)

  8(x -3) +3(y +1) = 0

  8x +3y -21 = 0

__

By the "cross multiplication method", the solution to these equations is ...

  x = (-3(-21) -(3(-13))/(7(3) -8(-3)) = (63+39)/(21+24) = 102/45 = 2 4/15 ≈ 2.27

  y = (-13(8) -(-21)(7))/45 = 43/45 ≈ 0.96

The orthocenter is near (2.27, 0.96).

__

A graphing application confirms this result.

_____

<em>Additional information about the cross multiplication method</em>

For the general form equations ...

  • ax +by +c = 0
  • dx +ey +g = 0

The "cross multiplication method" has you write the array ...

  \begin{array}{cccc}a&b&c&a\\d&e&g&d\end{array}

and form the "cross products" in groups of four coefficients:

  D = ae -db, X = bg -ec, Y = cd -ga

Then the solution to the set of equations is ...

  1/D = x/X = y/Y   ⇒   x = X/D, y = Y/D

__

<em>Additional note</em>

Videos of this method show you writing the array as bcab/egde and using the final equation x/X=y/Y=1/D. The above gets the same result in a more straightforward manner.

3 0
3 years ago
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