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Dennis_Churaev [7]
3 years ago
11

Please help find the measurement of exterior angle MBI

Mathematics
1 answer:
boyakko [2]3 years ago
7 0

Answer:

The measure of an exterior angle is found by the following formula: Aˆ0B=^AB-^CD2. An interior angle has its vertex at the intersection of two lines that intersect inside a circle. The sides of the angle lie on the intersecting lines. You can find a measure of an exterior angle of a regular polygon with  

N  sides.  It is equal to   360 o N .

Step-by-step explanation:  

Angles of a general polygon (exterior and interior) with more than 3 sides are not defined by the lengths of its sides.  

However, we can calculate the sum of all interior or exterior angles of any convex polygon. It equals to  360 o .

It can be proven geometrically since each exterior angle describes a rotation by some angle and a sum of all exterior angles describes a rotation by full angle of  

360 o . So, if all exterior angles are equal, like in a regular polygon, each one equals to  360 o N .

It can also be defined with some algebraic calculations based on the fact that a sum of all interior angles is  ( N − 2 ) ⋅ 180 o .  

Dividing the above by  N

we will obtain a value of an interior angle:  ( N − 2 ) ⋅ 180o N .  

Therefore, exterior angle of a regular polygon is  180 o − ( N − 2 ) ⋅ 180 o N = 360 o N

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Hi!

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Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC
e-lub [12.9K]

Answer:

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Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

BM^2=AB^2-AM^2

we have

AB=5\ units\\AM=x\ units

substitute

BM^2=5^2-x^2

BM^2=25-x^2 -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

BM^2=BC^2-MC^2

we have

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substitute

BM^2=7^2-(9-x)^2

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BM^2=49-81+18x-x^2

BM^2=-x^2+18x-32 ----> equation B

equate equation A and equation B

-x^2+18x-32=25-x^2

solve for x

18x=25+32\\18x=57\\\\x=\frac{57}{18}

Simplify

x=\frac{19}{6}

<em>Find the length of DC</em>

DC=AC-2x

substitute the given values

DC=9-2(\frac{19}{6})

DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units

8 0
3 years ago
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