16•16=256
A quarter is missing so 256/4=64
64•3=192 is the total square area.
When you find the area of a triangle you usually do (b•h)/2
Since this right here is equal triangles for both ways you can simply divide 192/2=96ft^2
Answer: Choice D)
S(x) = 6x^2 - 20x
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Explanation:
x = side length of base
x*x = x^2 = area of base
The top also has an area of x^2 since the base and top are both congruent squares. The total base area is x^2+x^2 = 2x^2
The height h is 5 inches shorter than the base, so
h = (base length) - 5
h = x-5
Each lateral side is of area h*x = (x-5)*x = x^2-5x
There are 4 lateral sides
Total lateral area = 4*(area of one lateral side)
Total lateral area = 4*(x^2-5x)
Total lateral area = 4*x^2-4*5x
Total lateral area = 4*x^2-20x
Add the total lateral area (4x^2-20x) to the total base area (2x^2)
Doing so gets us
S(x) = Total Surface Area
S(x) = (Area of bases) + (area of lateral sides)
S(x) = (2x^2) + (4x^2-20x)
S(x) = (2x^2+4x^2) - 20x
S(x) = 6x^2 - 20x
which is why the answer is choice D
Answer:
C. X=6 or X= -9
First Explanation:
2x + 3 - 3 = 15 - 3 (subtract 3 from 3 and 15)
You should get 2x = 12
Then divide 2x by 2
Divide 12 by 2 which you should get
X = 6
Second Explanation:
2x + 3 - 3 = 15 - 3 (subtract 3 from 3 and 15)
You should get 2x = -18
Then divide 2x by 2
Divide -18 by 2 and you should get
X = -9
Step-by-step explanation:
No of Student in Debre Berhan University - 80 students
<h2>
<em>No </em><em>of </em><em>student </em><em>good </em><em>in </em><em>mathematics </em><em>-</em><em> </em><em>45 </em><em>student's </em></h2>
<em>No </em><em>of </em><em>students </em><em>good </em><em>in </em><em>mathematics </em><em>and </em><em>English </em><em>-</em><em>15</em>
<h2><u>No </u><u>of </u><u>students </u><u>good </u><u>in </u><u>mathematics </u><u>and </u><u>psychology </u><u>-</u><u>13</u></h2>
<h2><u>No of students good </u><u>in </u><u>English </u><u>and </u><u>psychology </u><u>-</u><u>16</u></h2>
<h3><u>No of students good in</u><u> </u><u>psychology </u><u>-</u><u>20</u></h3>
<u>no </u><u>of </u><u>student </u><u>good </u><u>in </u><u>mathematics </u><u>-</u><u>45+</u><u>1</u><u>5</u><u>+</u><u>1</u><u>3</u>
<h2><u>-</u>
<em><u>7</u></em><em><u>5</u></em></h2>
<em><u>therefore </u></em><em><u>no </u></em><em><u>of </u></em><em><u>student </u></em><em><u>good </u></em><em><u>in </u></em><em><u>math </u></em><em><u>is </u></em><em><u>75 </u></em><em><u>.</u></em>
<em><u>pls </u></em><em><u>mark </u></em><em><u>me </u></em><em><u>branilest </u></em>