Answer:
Step-by-step explanation:
since AD is a median it implies that triangle ABC is bisected to two equal right angled triangle which are ADB and ADC.
FE is parrallel to BC and cuts AB at F and AC at E shows that there are two similar triangles formed which are AFE and ABC.
Recall that ADC is a right angled triangle, ED bisects a right angled triangle the the ADE = 
.
Now, Let FD bisect angle ADB,
then ADF = too.
Since AFX is similar to Triangle ABD and that Triangle AEX is similar to Triangle ACD, then EDX is similar to FDX
FDE = ADF + ADE = 
Let
x-------> the amount of 
solution
y--------> the amount of 
solution
we know that
so
-------> equation A
-------> equation B
substitute equation A in equation B
find the value of y
therefore
The student need 
of solution and 
of solution
<u>the answer is</u>
A) The percent values were written incorrectly in the equation
B) The amount of 7% solution should be written as 1 – x, not x – 1.
<span>t^-6 * t^2
= t^-4
hope it helps</span>
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Hello!
To be perpendicular to x = 4, the line must be y = something. This eliminates answer choices #2 and #4. Also, to pass through the point (.5, 7), the line must be y = 7.
So answer choice #3.
Hope this helps!! Let me know if you have ANY questions.
