Answer:
You could not use a table with a top that is 2 1/2 feet long and 1 1/2 feet wide
Step-by-step explanation:
<u><em>The complete question is</em></u>
Elena needs to find a table that will fit three cube-shaped cases, each containing a frog.If the volume of each case is 1,000 cubic inches, could she use a table with a top that measures 2 1/2 feet long and 1 1/2 feet wide?Explain
step 1
Find the length side of the cube-shaped case
we know that
The volume of the cube is equal to
where
b is the length side of the cube
we have
substitute
solve for b
step 2
Convert feet to inches
we have
step 3
Compare the dimensions of the table with the dimensions of the cube-shaped case
30 > 10
The length of the table is greater than the length side of the cube
18> 10
The width of the table is greater than the length side of the cube
therefore
You could not use a table with a top that is 2 1/2 feet long and 1 1/2 feet wide
First off 3/9 and 6/9 are already common denominators. In some fractions you would need to find the least common denominator like in a problem like 1/2 + 4/5. Also 3/9 plus 6/9 results in 9/9 and 9/9 equals 1. Most fractions adding it subtracting results in a pan answer as a fraction but in this case it’s a whole number.
Check out the image attachment for one way to draw this problem out. Notice how angles AEC and DEB are vertical angles, so that means they are congruent angles
(measure of angle AEC) = (measure of angle DEB)
6x + 20 = 10x
6x + 20-6x = 10x-6x ... subtract 6x from both sides
20 = 4x
4x = 20
4x/4 = 20/4 ... divide both sides by 4
x = 5
The value of x is 5.
Let's check the answer
6x + 20 = 10x
6*5 + 20 = 10*5 ... replace every x with 5
30+20 = 50
50 = 50
We have confirmed the answer.