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maria [59]
3 years ago
13

Distance between (8,-11) and (-6,9) to the nearest tenth

Mathematics
1 answer:
Leto [7]3 years ago
5 0
Could you tell me what the question is?
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Write the slope-intercept form of the equation of the line that passes through (-3,1) and is parallel to the line represented by
Shalnov [3]
 assume you want a line that goes through the given point and parallel to the given line. A line that is parallel to y=2/3 x + 5 will have the same slope. slope of that line is 2/3...the number in front of the x. So our new line will have slope of 2/3. now we need the y-intercept. To find that start with a slope intercept equation y=mx+b plug in the slope that we already know...it goes in for x...will be the number in front of x y= 2/3 x + b. now all we need is a number to plug in for the "b" and we will have it. to get the "b"...start with the part you already know. y = 2/3 x + b use the point they gave you...(-3,1)...and get x and y from it x will be -3 and y will be 1 plug that in 1= 2/3 ( -3) + b now we solve for b 1 = -2 + b 3 = b now we have the b we need y = 2/3 x + b y = 2/3 x + 3 
8 0
3 years ago
WILL MARK BRAINLIEST A number cube is rolled and a coin is flipped. Predict how many times you would get heads and a number grea
Over [174]

Answer:

coin flip is 1/2

2 numbers are less than 3 so 2/6 = 1/3

1/2 x 1/3 = 1/6 probability total

240 x 1/6 = 40

answer is C) 40

Step-by-step explanation:

8 0
3 years ago
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An item is regularly priced at $33. It is now priced at a discount of 65% off the regular price.
Vinil7 [7]
Step by step explanation:

33 x .65 = 21.45

33 - 21.45 = 11.55

The total of the discounted item is $11.55.
3 0
2 years ago
Write an equation of the line below ​
Yuki888 [10]

Answer:

ok.

Step-by-step explanation:

y=-1/1x+4. hope this helped :))

3 0
2 years ago
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Estimates of the number of cells in the human body vary over an order of magnitude.​ Indeed, the precise number varies from one
Amiraneli [1.4K]

Answer:

a) 2.00 × 10¹⁰;  b) 2.00 × 10¹³

Step-by-step explanation:

a) No. of cells in 1 cm³

\text{No. of cells} =\text{1 cm}^{3} \times\left( \dfrac{\text{1 m}}{\text{100 cm}}\right )^{3} \times \left (\dfrac{1 \, \mu \text{m} }{10^{-6}\,\text{ m}}\right )^{3} \times  \dfrac{\text{1 cell}}{\text{50 $\,\mu$m}^{3}} = \mathbf{2.00 \times 10^{10}} \textbf{ cells}

b) No. of cells in 1 L

\text{No. of cells} =  \text{1 L} \times \dfrac{\text{1000 cm}^{3}}{\text{1 L}} \times \dfrac{2 \times 10^{10} \text{ cells}}{\text{1 cm}^{3}} = \mathbf{2.00 \times 10^{13}} \textbf{ cells}

7 0
3 years ago
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