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3 years ago

2) Write an equation that passes through the point (-2,5) and is parallel to y ==x+1.

Mathematics

1 answer:

Marta_Voda [28]3 years ago

4 0

Answer:

y = x + 7

Step-by-step explanation:

5 = -2 + b

7 = b

y = x + 7

* Parallel lines have SIMILAR RATE OF CHANGES [SLOPES], so 1 remains the way it is.

I am joyous to assist you anytime.

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On each trial of an experiment, a subject is presented with a constant soft noise, which is interrupted at some unpredictable ti

Julli [10]

Answer:

25th percentile = 202

80th percentile = 285

Step-by-step explanation:

Rearranging the values in increasing order

164

171

175

202

217

226

231

241

257

261

269

273

285

296

311

N = total number of variables = 15.

25th percentile = [(N + 1)/4]th variable = (15 + 1)/4 = 4th variable.

So, the 25th percentile = 4th variable = 202.

80th percentile = 0.8(N + 1) th variable = 0.8 × (15 + 1) = 12.8th variable = 13th variable = 285

6 0

3 years ago

The cost to rent an instrument is $05 for the first month. It costs $30 for each additional

mihalych1998 [28]

Answer:

total cost, or c = number of months rented after first month, or x, times $30 + $5

c=30x+5

Step-by-step explanation:

6 0

3 years ago

I need help with this problem

Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒ $cosA=\frac{u.v}{|u||v|}$

Given u=-8i-3j and v=-8i+8j

$|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544$

$|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137$

let A be angle before u and v

therefore, $cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}$

⇒ $A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56$

Therefore angle between u and v is 65.56°

5 0

2 years ago

Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights

Fed [463]

Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

Given that, A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171, Z = (4171 - 3311)/860 = 1

P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171

For part b, use the same method except x is now 1591.

Z = (1581 - 3311)/860 = -2

P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

5 0

2 years ago

A local citizen wants to fence a rectangular community gardenn. The length of the garden should be at least 110ft,and the distan

Arte-miy333 [17]

The question is incorrect
the correct question is
A local citizen wants to fence a rectangular community garden. The length of the garden should be at least 110 ft,and the distance around should be no more than 380 ft. Write a system of inequality that model the possible dimensions of he garden. Graph the system to show all possible solutions

let
x---------------> the length of the garden
y---------------> the wide of the garden

we know that
x>=110
2x+2y <=380---------------> x+y <= 190

Part A) Write a system of inequality that model the possible dimensions of he garden

the answer part A) is
x>=110
x+y <= 190

Part B) Graph the system to show all possible solutions

using a graph tool
see the attached figure
the solution is the triangle show in the figure

the possible solutions of y (wide) would be between 0 and 80 ft
the possible solutions of x (length) would be between 110 ft and 190 ft

5 0

3 years ago