Answer:
15000(1.003425)^12t ;
4.11%
4.188%
Step-by-step explanation:
Given that:
Loan amount = principal = $15000
Interest rate, r = 4.11% = 0.0411
n = number of times compounded per period, monthly = 12 (number of months in a year)
Total amount, F owed, after t years in college ;
F(t) = P(1 + r/n)^nt
F(t) = 15000(1 + 0.0411/12)^12t
F(t) = 15000(1.003425)^12t
2.) The annual percentage rate is the interest rate without compounding = 4.11%
3.)
The APY
APY = (1 + APR/n)^n - 1
APY = (1 + 0.0411/12)^12 - 1
APY = (1.003425)^12 - 1
APY = 1.04188 - 1
APY = 0.04188
APY = 0.04188 * 100% = 4.188%
-24 + y= -120
y= -96 is the answer to the problem
200t + 8t^3 - 80t^2
8t(25 + t^2 - 10t) ....rearrange
8t(t^2 - 10t + 25)
8t(t - 5)(t - 5)
8t(t - 5)^2 <==
Answer:

Step-by-step explanation:
Use the slope formula so y2 - y1 / x2 - x1 [the numbers are subscripts]
So -8 - (-3) / -2 - (-6) so -8+3/-2+6, therefore -5/4