Which inequality represents all possible solutions of ? A. B. C. D.

I keep getting several answers, and I’m not sure how to solve this ? Help me pleaseee!!

algol [13]

Answer:

Perimeter= 44.2 inches

Area= 70 inches squared

Step-by-step explanation:

Perimeter- Add all your sides together (10+ 17.2+2+3+7+5=44.2)

Area- 1/2bh (b=base, h=height)

Your base is the bottom of the triangle, so 2+7+5=14.

14 is your base

Your height is the 10

1/2 *14*10

1/2 of 14 is 7

7*10= 70

Don't forget to write inches squared or it will be wrong

Hope this helps :)

5 0

3 years ago

Read 2 more answers

Classify the system and determine the number of solutions. Check all that apply. {7x + y = 13 28x + 4y = -12 A) inconsistent B

Ostrovityanka [42]

$\left\{\begin{array}{ccc}7x+y=13&|multiply\ both\ sides\ by\ (-4)\\28x+4y=-12\end{array}\right\\+\left\{\begin{array}{ccc}-28x-4y=-52\\28x+4y=-12\end{array}\right\ \ \ |add\ the\ sides\ of\ the\ equations\\------------\\.\ \ \ \ \ \ \ \ 0=-64-FALSE\\\\Answer:A)\ inconsistent\ and\ D)\ no\ solution.$

4 0

3 years ago

A taxi travels 25 kilometers east of an airport. Then it travels from that point to a point that is 40 kilometers west of the ai

kati45 [8]

25km east + 25km return+ 40km west + 40km return = 130km

Hope that helped :)

7 0

3 years ago

Help with matrice equations

Tasya [4]

Answer:

21) x=1, y=-1, z=2 and 23) x=3, y=-1, z=-1

Step-by-step explanation:

there are 3 equations in 21)

1) x+y-z=-2

2)2x-y+z=5

3)-x+2y+2z=1

solve for x by adding equation 2) and 1)

2)2x-y+z=5 + 1) x+y-z=-2 = 3x=3, then divide by 3 and x=1

solve for z by adding equation 1) and 3)

1) x+y-z=-2 + 3)-x+2y+2z=1

we then get a new equation, 4), by isolating z

3y+z=-1 which is 4) z=-1-3y

substitute our new equation, 4) z=-1-3y, and x=1 into equation 1) to get y

(1)+y- (-1-3y)=-2

isolate y to get y=-1

then substitute y=-1 into equation 4) to get z=2

check by substituting x=1, y=-1, and z=2 into all 3 equations

there are 3 equations

1)x+3y=0

2)x+y+z=1

3)3x-y-z=11

add equation 3) and 2) together to get x

3)3x-y-z=11 + 2)x+y+z=1

4x=12, x=3

substitute x=3 into equation 1) (3)+ 3y=0 to get y

3y=-3, y=-1

substitute x=3 and y=-1 into equation 2) to get z

(3)+(-1)+z=1, z=-1

4 0

3 years ago

Axis of symmetry: x=4; points: (3,-2), (6,-26); opening downward

Andru [333]

Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k

we have some points
(3,-2) and (6,-26)
input and solve for a and k

(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k

(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k

we have

-2=a+k
-26=4a+k
multiply first equation by -1 and add to second

2=-a-k
-26=4a+k +
-24=3a+0k

-24=3a
divide both sides by 3
-8=a

-2=a+k
-2=-8+k
add 8 to both sides
6=k

the equation is
$y=-8(x-4)^2+6$

3 0

3 years ago