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kaheart [24]
4 years ago
15

I need to find AB and DE​

Mathematics
1 answer:
MatroZZZ [7]4 years ago
4 0

Answer:

AB = 21 and DE = 23

Step-by-step explanation:

Given 2 intersecting chords inside the circle then

The products of the measures of the parts of one chord is equal to the products of the measures of the parts of the other chord, that is

x(x + 13) = (x + 10)(x + 1) ← distribute parenthesis on both sides

x² + 13x = x² + 11x + 10 ← subtract x² + 11x from both sides

2x = 10 ( divide both sides by 2 )

x = 5

Hence

AB = x + 10 + x + 1 = 2x + 11 = (2 × 5) + 11 = 10 + 11 = 21

DE = x + x + 13 = 2x + 13 = (2 × 5) + 13 = 10 + 13 = 23

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