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2 years ago

Please find the missing side of this triangle

Mathematics

1 answer:

Strike441 [17]2 years ago

7 0

The answer is 15.01

First you need to find the other angle of the triangle so you do 90+25 which gives you 115 and subtract that by 180 because all angles of a triangle add up to 180. That gives you 65 then you will use TAN(65) and get 2.144506920509559 which you will then multiple by 7 to get 15.01154844356691 which you then round to get 15.01!

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Consider the function f(x) = x² – 3x – 4 and complete parts (a) through (C). (a) Find f(a+h); f(a+h)-f(a) (b) Find (c) Find the

Artist 52 [7]

Answer:

(a)

$f(a+h)=a^{2} +2ah+h^{2} -3a-3h-4$

(b)

$f(a+h)-f(a)=2ah+h^{2} -3h$

(c)

$\frac{df(a+h)}{dx} \left \{ { \atop {a=7}} \right. =2h+11$

Step-by-step explanation:

(a)

Simply evaluate (a+h) in the function:

$f(a+h)=(a+h)^{2} -3(a+h)-4=a^{2} +2ah+h^{2} -3a-3h-4$

(b)

Evaluate (a) in the function:

$f(a)=a^{2} -3a-4$

Using the previous answers lets calculate f(a+h)-f(a)

$f(a+h)-f(a)=a^{2} +2ah+h^{2} -3a-3h-4-(a^{2} -3a-4)=2ah+h^{2} -3h$

$\frac{df(a+h)}{dx} \left \{ { \atop {a=7}} \right. =2a+2h-3=2(7)+2h-3=2h+14-3=2h+11$

7 0

2 years ago

Use the law of cosines to find the length of a

borishaifa [10]

Answer:

Step-by-step explanation:

You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:

$\frac{sin55}{175}=\frac{sin42}{a}$ and solving for a:

$a=\frac{175sin42}{sin55}$ so

a = 143.0

4 0

2 years ago

Subtract:<br> 3 3/5 -1 1/1<br> 1 1/10<br> 2 1/10<br> 2 1/5<br> 2 2/3

VARVARA [1.3K]

Step-by-step explanation:

3 3/5 - 1 1/10

3 6/10 - 1 1/10

2 2/10= 2 1/5 is the answer

5 0

2 years ago

What are the domain and range of the inequality y < sqrt x+3+1

love history [14]

Given:

The inequality is:

$y$

To find:

The domain and range of the given inequality.

Solution:

We have,

$y$

The related equation is:

$y=\sqrt{x+3}+1$

This equation is defined if:

$x+3\geq 0$

$x\geq -3$

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

$\sqrt{x+3}\geq 0$

$\sqrt{x+3}+1\geq 0+1$

$y\geq 1$

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

So, the domain of the given inequality is y>1.

Therefore, the correct option is A.

3 0

2 years ago

Natali [406]

The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.

<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>

Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.

On this note, since the task content suggest that the ratio of the perimeters is; 1:10, it follows from conventional mathematics that the ratio of their areas is given as; 1²:10²; 1:100.