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Lena [83]
2 years ago
15

Anybody know the answer?

Mathematics
1 answer:
Reika [66]2 years ago
6 0

I’m pretty sure it should be cos + cos

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Bens mom wants to buy carpet for the family room the measures 12 feet by 11 feet she can purchase the carpet on sale for $6 how
podryga [215]
12 times 11 is 132.
132 times $6 is $792

Hope this helps!
7 0
2 years ago
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a mechanic buys $14.56 worth of parts from a supplier. if he pays for the parts with a $20 bill, how much change will he receive
Bond [772]
He will receive $5.04
3 0
3 years ago
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Jimmy invests $7,000 in an account that pays 3% interest compounded semi-annually. What is his balance after 8 years?
Bumek [7]

Answer:

$8882.9

Step-by-step explanation:

A=p(1+(r/n))^nt

Given:P=7000, r=(3÷100%)=0.03 , n=2, t=8

A = 7000(1+(.03/2))^(2×8)

A = 7000 (1+0.015)^16

A = 7000 × 1.015^16

A = $8882.9

7 0
2 years ago
A piece of toast came out of the toaster very overcooked.
Nikitich [7]

Answer:

It is a chemical change ⇒ 1st answer

Step-by-step explanation:

* Lets explain the statements to solve the problem

- <u><em>A chemical change</em></u> occurs when a new substance is formed through

 a chemical reaction

- Ex: cooking an egg

- <u><em>Change of reaction</em></u> is the rate of reaction it can be decreases or

  increasing

- <u><em>A phase change</em></u> is a change from one state to another without a

 change in chemical composition

- Ex: Condensation: the substance changes from a gas to a liquid

- <u><em>A physical change</em></u>, such as a state change or dissolving, but does

 not create a new substance

- Ex: Breaking a glass

* Lets solve the problem

- A piece of toast came out of the toaster very overcooked.

∵ It is like the cooking an egg

∴ It is a chemical change

7 0
3 years ago
Find four numbers that form a geometric progression such that the third term is greater than the first by 12 and the fourth is g
olchik [2.2K]

If x is the first number in the progression, and r is the common ratio between consecutive terms, then the first four terms in the progression are

\{x,xr,xr^2,xr^3\}

We want to have

\begin{cases}xr^2-x=12\\xr^3-xr=36\end{cases}

In the second equation, we have

xr^3-xr=xr(r^2-1)=36

and in the first, we have

xr^2-x=x(r^2-1)=12

Substituting this into the second equation, we find

xr(r^2-1)=12r=36\implies r=3

So now we have

\begin{cases}9x-x=12\\27x-3x=36\end{cases}\implies x=\dfrac32

Then the four numbers are

\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}

4 0
3 years ago
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