Answer:
E1 and E2 are not mutually exclusive events. They have outcomes in common because a winning number can be both red and odd.
Step-by-step explanation:
EDMENTUM
Answer:
Option 4: <u>(2x + 16)° + (x)° = 180°</u>
Step-by-step explanation:
See the attached figure.
For a quadrilateral inscribed in a circle
The opposite angles are supplementary.
So, ∠D + ∠B = 180°
From the figure:
∠B = x° and ∠D = (2x+16)°
∴ <u>(2x + 16)° + (x)° = 180°</u>
the simple equation you have to do is
0.15 x 50,000 or 15% of 50,000 of which both equations will result in 7500
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
b^2-4(1)(16) ≥ 0
</span><span>b^2-64 ≥ 0
(b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
