Answer:
E1 1,3,5,7,9,12,14,16,18,19,21,23,25,27,30,32,34,36
E2 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35
E1 & E2 1,3,5,7,9,19,21,23,25,27
E1 or E2 2,4,6,8,10,20,22,24,26,28,0,00
Step-by-step explanation
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E1 and E2 are not mutually exclusive events. They have outcomes in common because a winning number can be both red and odd.
Step-by-step explanation:
EDMENTUM
We have these following probabilities:
40% probability that the first file is corrupted. So 60% probability that the first file is not corrupted.
30% probability that the second file is corrupted. So 70% probability that the second file is not corrupted.
Probability mass function
Probability of each outcome(0, 1 and 2 files corrupted).
No files corrupted:
60% probability that the first file is not corrupted.
70% probability that the second file is not corrupted.
So
One file corrupted:
First one corrupted, second no.
40% probability that the first file is corrupted.
First one ok, second one corrupted.
30% probability that the second file is corrupted.
Two files corrupted:
(6,-7)
subtract them:
-8x - 5y = -13
-4x - 5y = 11
you get
-4x = -24
so x = 6
plug x into the second equation:
-24 - 5y = 11
-5y = 35
y = -7
so your solution is (6,-7).
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