Assuming is differentiable over the interval (1, 5), by the mean value theorem we know that there is some
such that
We're given that for all
, so
that is, the minimum possible value is 8, and the maximum possible value is 12.
What is the answer for this question-7x-2y=-13
1 answer:
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Answer:
< 1 = 130°, < 2 =50°, < 3 = 50°, < 4= 30°, < 5 = 70°, < 6 = 50°, < 7= 60°, < 8 = 40°, < 9 = 40°, < 10 = 50°, < 11 = 50°, < 12 = 130°, < 13 = 140°, < 14 =40° , < 15 = 140°
Step-by-step explanation:
< 4 = 90- 60 = 30° because angle 4 and angle 60° are complementary
< 5 = 70°, because vertical angles are congruent
< 2 = 180-130 = 50 °, because 130 ° and 2 are a linear pair
< 6 = 180-130 = 50 °, because 130 ° and 2 are a linear pair
because < 2 = < 6 and are alternate exterior angles then two lines are parallel
<13 = 140°, corresponding angles
< 13 = < 15 = 140°, vertical angles
< 8 = < 9 = < 14 = 180-140 = 40°, linear pair and vertical angles
< 3 = 180-90-40= 50 °, because the sum off all angles in a Δ is 180°
< 3= < 10 = < 11 =50° vertical angles , and corresponding angles
< 7= 180 -70 -50 = 60°, because the sum off all angles in a Δ is 180°
<1 = <12 = 180 -50 = 130°, linear pair and vertical angles
