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tiny-mole [99]
2 years ago
6

If each interior angle of a regular polygon measures ​120 , how many sides does the polygon​ have?

Mathematics
2 answers:
Tom [10]2 years ago
6 0

\huge\sf{Answer :- }

<h2>Given :- </h2>

  • Each interior angle of regular polygon is 120°

<h2>To Find :- </h2>

  • Number of sides of the polygon

<h2>Formula :- </h2>

Interior angle of the polygon = [180(n - 2)]/n

where,

  • n = sides of the polygon

<h2>Solution :- </h2>

Let, The number of sides of polygon be n

<h3>By substituting values according to the formula,</h3>

➯ [180(n - 2)]/n = 120°

➯ 180n - 360 = 120n

➯ 180n - 120n = 360

➯ 60n = 360

➯ n = 360/60

➠ n = 6

<h3><u>Hence, The regular polygon have 6 sides</u></h3>
KatRina [158]2 years ago
3 0

Answer:

the ans is 6 sides i guess

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Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

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Step-by-step explanation:

Since we have given that

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Now,

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1\text{ pound}=16\text{ ounces}

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\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}

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1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .


4 0
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