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tiny-mole [99]
2 years ago
6

If each interior angle of a regular polygon measures ​120 , how many sides does the polygon​ have?

Mathematics
2 answers:
Tom [10]2 years ago
6 0

\huge\sf{Answer :- }

<h2>Given :- </h2>

  • Each interior angle of regular polygon is 120°

<h2>To Find :- </h2>

  • Number of sides of the polygon

<h2>Formula :- </h2>

Interior angle of the polygon = [180(n - 2)]/n

where,

  • n = sides of the polygon

<h2>Solution :- </h2>

Let, The number of sides of polygon be n

<h3>By substituting values according to the formula,</h3>

➯ [180(n - 2)]/n = 120°

➯ 180n - 360 = 120n

➯ 180n - 120n = 360

➯ 60n = 360

➯ n = 360/60

➠ n = 6

<h3><u>Hence, The regular polygon have 6 sides</u></h3>
KatRina [158]2 years ago
3 0

Answer:

the ans is 6 sides i guess

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Answer:

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3) The middle value (Median)

4) The third (upper) quartile

5)The maximum value

Now, the given data is  4.0, 1.0, 1.5, 1.6, 2.0, 2.2, 2.4, 2.7, 3.4, 3.4, 3.5, 3.6, 3.6, 3.7, 3.7, 3.9, 4.1, 5.8, 4.1, 7.3

Arrange it in the ascending order,

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1) The minimum Value  is 1.0

2)The first (lower) quartile  is  2.3.

3) The middle value (Median)  is 3.5.

4) The third (upper) quartile is  3.95.

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