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Mashcka [7]
3 years ago
7

On a map two cities are 6 3/4 inches apart. The scale of the map is 1/4 inch= 10 miles. What is the actual distance between the

two cities?
Mathematics
1 answer:
Murljashka [212]3 years ago
3 0
27 times 10 = 270 miles apart.
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Order the following decimals from least to greatest. 9.036, 9.982, 9.535
Leona [35]
The order is: 9.036, 9.535, and 9.982.
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The angels of a triangle have a sum of 180°. The angles of a rectangle have a sum of 360°. The angels of a pentagon have a sum o
Airida [17]

Step-by-step explanation:

It is given that the angels of a triangle have a sum of 180°. The angles of a rectangle have a sum of 360°. The angels of a pentagon have a sum of 540.

<u>Let me define the each terms.</u>

1. We know that each angle in a triangle is 60°, So there is a three angle in a regular triangle.

  • 60° + 60° + 60°
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2. We know that each angle in a rectangle, is 90°, So there is a four angle in a regular rectangle.

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Similarly,

  • There is 8 angle in a regular octagon and each angle measurement is 135°.

So, sum of the angles of an octagon = 135° × 8

Sum of the angles of an octagon = 1080°

Therefore, the required sum of the angles of an octagon is 1080°

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3 years ago
Question 1<br><br> Which choice shows a 90° clockwise rotation of the figure about the point P?
Arada [10]
The third one is correct.....so go for it without hesitation
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The function ƒ(x) = (x − 1)^2 + 5 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an i
melisa1 [442]

Answer:

f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.

Step-by-step explanation:

The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.

* if x>1, then x-1>0.

* Also since the parabola opens up, then y>5.

So let's solve y=(x-1)^2+5 for x.

Subtract 5 on both sides:

y-5=(x-1)^2

Take square root of both sides:

Plus/minus sqrt(y-5)=x-1

We want x-1>0:

Sqrt(y-5)=x-1

Add 1 on both sides:

Sqrt(y-5)+1=x

Swap x and y:

Sqrt(x-5)+1=y

x>5

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3 0
3 years ago
Solve for z. z/12=6 3/4
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6 3/4=6*4+3/4=24+3/4=27/4

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Read 2 more answers
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