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3 years ago

An altitude of a triangle is a perpendicular segment from a vertex to the line containing the opposite side true or false

1 answer:

3 0

The answer is true. An altitude of a triangle is the perpendicular segment from a vertex to the line containing the opposite side.

You might be interested in

Multiply. Answer as a fraction. Do not include spaces in your answer 5 1/6•(-2/5) =???

Ne4ueva [31]

Answer:

2 1/15

Step-by-step explanation:

Hey there!

Well to multiply,

5 1/6 • -2/5,

we need to make 5 1/6 improper

$\frac{31}{6} * -\frac{2}{5}$

31 * 2 = 62

6 * 5 = 30

$-\frac{62}{30}$

Simplified,

$\frac{31}{15} \\Proper\\2 \frac{1}{15}$

2 1/15

Hope this helps :)

3 0

3 years ago

The number of patients treated at Dr. McCormick’s dentist office each day was recorded for nine days. These are the data: 13, 16

arlik [135]

Hi!

Let's start with the mean.

The mean is all the numbers added together, divided by how many numbers there are.

13+16+16+10+6+12+4+12+16=105
there are 9 numbers so..
105/9 = 11.7

The mean is 11.7

Find the median.

The median is the number in the middle of the data set when the numbers are in numerical order.

4, 6, 10, 12, 12, 13, 16, 16, 16

The median is 12.

Find the mode.

The mode is the number that is repeated the most.

4, 6, 10, 12, 12, 13, 16, 16, 16

The mode is 16

Find the range.

The range is the difference of the smallest number from the biggest number.

16 - 4 = 12

The range is 12

The answer is 11.7, 12, 16, 12

Hope this helps! :)

4 0

3 years ago

Help me with this question below

lutik1710 [3]

See attached picture for steps and answer:

3 0

3 years ago

Show work please \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

4 0

2 years ago

Ratio of 15 days over 3 jobs

Ann [662]

You need to divide the two numbers. 15/3 = 5

For every 5 days you do 1 job

5:1

7 0

4 years ago