The measure of angle 1 and 2 should add up to 180°, because it forms a straight line. The same goes for the sum of angle 3 and 4.
Since we are given the measure of angle 2, we can find the measure of angle 1 by subtracting 143° from 180°.
180°-143° = 37°
We know that the intersecting lines form 2 sets of vertical angles, which are congruent. This means that the angles opposite from each other have the same measure. Therefore, both angle 2 & 4 have a measure of 143°, while angle 1 & 3 have a measure of 37°.
Answer:
Hence the carnival game gives you better chance of winning.
Step-by-step explanation:
Let the event of win be given by 1/10 in the game of rifle then the event of loose is given by 9/10
the
Odds in favor of a game are given by = P(Event)/ 1- P(Event)
Odds in favor of winning a rifle are given by = 1/10/ 1- 1/10
=1/10/9/10
=1/9
= 0.111
The probability of winning aa rifle game is 0.111
The probability of winning the carnival game is 0.15
Comparing the two probabilities 0.111:0.15
The probability of winning carnival game is greater than winning a rifle game
0.15>0.11
Hence the carnival game gives you better chance of winning.
Based on the exchange rate, at the end of the trade, Lewis will have 31 puppets and 2 puzzles left over while Geppeto will have 158 puzzles and 4 puppets left over.
<h3>What is the exchange rate of puzzles for puppets?</h3>
The exchange rate of puzzles for puppets is 3 to 1.
Geppeto has 20 puppets to exchange for puzzles.
Lewis has 50 puzzles to exchange for puppets.
Number of times Lewis can exchange puzzles for puppets = 50/3 = 16 times.
Lewis will get 16 puppets in exchange for 48 puzzles.
Therefore;
Lewis will have 16 + 25 puppets = 31 puppets and 2 puzzles left over
Geppeto will have 48 + 100 puzzles = 158 puzzles and 4 puppets left over.
in conclusion, the exchange rate determines the how many puzzles and puppets will each one have after they complete their trade.
Learn more about exchange rate at: brainly.com/question/2202418
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Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
