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pav-90 [236]
3 years ago
9

I need to get the answers for the blanks

Mathematics
1 answer:
Tema [17]3 years ago
6 0
Is it a rhombus or is it just a parallelogram?
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Show all you're work!! Point's and will mark brainliest
Musya8 [376]

Answer:

d = 7.2

Step-by-step explanation:

Step 1: Write out equation

d/1.2 = 6

Step 2: Multiply both sides by 1.2

d = 7.2

4 0
3 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
Please help I’m begging
malfutka [58]

Answer:

69

Step-by-step explanation:

3 0
2 years ago
On Tuesday Clary and Mayla both ran for two and a half hours who ran the farther distance
Ksenya-84 [330]
No one because their is no fractions Or whole numbers or even decimals to show the amount that they ran please check to see if their is any other part to this question
4 0
3 years ago
6. Examine the prism shown below.
bulgar [2K]
It may be can be number 1 (a)
8 0
2 years ago
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