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kozerog [31]
3 years ago
15

Quadrilateral KLMN has vertices of K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4) Find the length of MN

Mathematics
1 answer:
Olenka [21]3 years ago
3 0

Answer:

The length of MN is \sqrt{5} units.

Step-by-step explanation:

The given Quadrilateral KLMN has vertices at K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4).

We use the distance formula to find the length of MN.

|MN|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We plug in the values to get

|MN|=\sqrt{(-4--2)^2+(-4--5)^2}

|MN|=\sqrt{(-2)^2+(1)^2}

|MN|=\sqrt{4+1}

|MN|=\sqrt{5}

The length of MN is \sqrt{5} units.

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<em> </em><em>-</em><em>1</em>

Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>The </em><em>value</em><em> of</em><em> x</em><em> </em><em>=</em><em> </em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>The </em><em>value</em><em> of</em><em> </em><em>y </em><em>=</em><em> </em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>we </em><em>need</em><em> to</em><em> find</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>y)</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>so,</em><em> </em><em>put </em><em>the </em><em>value </em><em>of </em><em>above</em><em> </em><em>variables</em><em> </em><em>in </em><em>it</em>

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<em> </em><em> </em><em> </em><em> </em><em> </em><em>hope</em><em> it</em><em> helps</em>

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