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kozerog [31]
3 years ago
15

Quadrilateral KLMN has vertices of K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4) Find the length of MN

Mathematics
1 answer:
Olenka [21]3 years ago
3 0

Answer:

The length of MN is \sqrt{5} units.

Step-by-step explanation:

The given Quadrilateral KLMN has vertices at K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4).

We use the distance formula to find the length of MN.

|MN|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We plug in the values to get

|MN|=\sqrt{(-4--2)^2+(-4--5)^2}

|MN|=\sqrt{(-2)^2+(1)^2}

|MN|=\sqrt{4+1}

|MN|=\sqrt{5}

The length of MN is \sqrt{5} units.

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There is another solution you can find the vertex point (h , k) of the graph of the quadratic equation y = ax² + bx + c, where h = -\frac{b}{2a} and k is the value of y at x = h and k is the maximum/minimum value

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