Use your graphing calculator to determine if the equation appears to be an identity or not by graphing the left expression and r
ight expression together. If so, verify the identity. If not, find a counterexample. sec x + cos x = tan x sin x
1 answer:
Answer:
![(sec x)+(cos x)=(tan x)*(sin x)\\identities\\(sec x)= 1/cos x\\(tan x)=sin x/cos x\\\\and\\(cos x)^{2}+(sin x)^{2}=1\\(cos x)^{2}=1-(sin x)^{2}\\\\(1/cos x )+(cos x) = (sin x)*(sin x)/(cos x)\\ [(1/cos x)+(cos x)]*(cos x)=(sin x)^{2}\\\\1+(cos x)^{2}=(sin x)^{2}\\1+1-(sin x)^{2}=(sin x)^{2}\\2=2*(sin x)^{2}\\2/2=(sin x)^{2}\\1=(sin x)^{2}\\\\This is not true ,so\\(sec x)+(cos x)\neq (tan x)*(sin x)](https://tex.z-dn.net/?f=%28sec%20x%29%2B%28cos%20x%29%3D%28tan%20x%29%2A%28sin%20x%29%5C%5Cidentities%5C%5C%28sec%20x%29%3D%201%2Fcos%20x%5C%5C%28tan%20x%29%3Dsin%20x%2Fcos%20x%5C%5C%5C%5Cand%5C%5C%28cos%20x%29%5E%7B2%7D%2B%28sin%20x%29%5E%7B2%7D%3D1%5C%5C%28cos%20x%29%5E%7B2%7D%3D1-%28sin%20x%29%5E%7B2%7D%5C%5C%5C%5C%281%2Fcos%20x%20%29%2B%28cos%20x%29%20%3D%20%28sin%20x%29%2A%28sin%20x%29%2F%28cos%20x%29%5C%5C%20%5B%281%2Fcos%20x%29%2B%28cos%20x%29%5D%2A%28cos%20x%29%3D%28sin%20x%29%5E%7B2%7D%5C%5C%5C%5C1%2B%28cos%20x%29%5E%7B2%7D%3D%28sin%20x%29%5E%7B2%7D%5C%5C1%2B1-%28sin%20x%29%5E%7B2%7D%3D%28sin%20x%29%5E%7B2%7D%5C%5C2%3D2%2A%28sin%20x%29%5E%7B2%7D%5C%5C2%2F2%3D%28sin%20x%29%5E%7B2%7D%5C%5C1%3D%28sin%20x%29%5E%7B2%7D%5C%5C%5C%5CThis%20is%20not%20true%20%2Cso%5C%5C%28sec%20x%29%2B%28cos%20x%29%5Cneq%20%28tan%20x%29%2A%28sin%20x%29)
You might be interested in
Answer:
True, since 1 is 1/1, which is 100%
<em>Hope that helps! :)</em>
Step-by-step explanation:
Answer:
Line AC is 9.01 cm
Angle A is 33.7
Angle C is 56.3
Step-by-step explanation:
5,000 is the answer to the equation
Are a and b two points on a line
If they are you can use the distance formula
