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Lelechka [254]
3 years ago
13

StartFraction 12 minus 3 y Over 2 EndFraction plus y StartFraction 2 y minus 4 Over y EndFraction for y = 3.

Mathematics
2 answers:
Neko [114]3 years ago
7 0
Answer:
Step-by-step explanation:
The point slope form of the equation is expressed as
y - 7/2 = 1/2(x - 4)
Comparing with the point slope form of an equation which is expressed as
y - y1 = m(x - x1)
m represents slope
Therefore
m = 1/2
y1 = 7/2
x1 = 4
The slope intercept form of the equation of a straight line is expressed as
y = mx + c
Where c represents the intercept
Substituting y = 7/2, m = 1/2 and x = 4 into y = mx + c, it becomes
7/2 = 1/2 × 4 + c
7/2 = 2 + c
c = 2 - 7/2 = (4 - 7)/2 = - 3/2
Therefore, the y intercept is - 3/2
grin007 [14]3 years ago
4 0

Answer:

3.5

Step-by-step explanation:

i took the class edg.2020

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3 years ago
Can people please help me on this
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7 0
3 years ago
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svlad2 [7]
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3 0
2 years ago
Read 2 more answers
Solve the following system of equations by elimination​
olya-2409 [2.1K]

Answer:

y = -6

x = 1

Step-by-step explanation:

-x + 2y = -13

-x - 2y = 11

Sum the equations:

-x -x = -2x

+2y - 2y = 0

-13 + 11 = -2

then

-2x = -2

x = -2/-2

x = 1

from the first eq.

-x + 2y = -13

-1 + 2y = -13

2y = -13 + 1

2y = -12

y = -12/2

y = -6

check:

from the second eq.

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5 0
2 years ago
If a jogger runs 2 miles and burns 185 calories, how many calories would he burn if he jogged 3 miles?
aliina [53]

The total amount of calories burnt in jogging 2 miles = 185 calories

We have to determine the number of calories burned in jogging 3 miles.

Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.

So, the total amount of calories burnt in jogging 1 mile = 185 \div 2

= 92.5 calories

So, the amount of calories burnt in 3 miles = 3 \times 92.5

= 277.5 calories

Therefore, 277.5 calories are burned in jogging 3 miles.

6 0
3 years ago
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