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mr_godi [17]
3 years ago
7

Ilwhats tge answerpleasee

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

B is your correct answer

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The average daily temperature in krez town went from -15 degrees in february to 47 degrees in march. what was the change in temp
ser-zykov [4K]

The change in temperature of Krez is 62 degrees.

According to the given question.

The temperature of Krez in February was -15 degerees.

And the temeperature of Krez in March was 47 degrees.

Therefore,

The change in temperature of Krez

= 47 degrees - (-15 degrees)

= (47 + 15)degrees

= 62 degrees

Hence, the change in temperature of Krez is 62 degrees.

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1 year ago
What do you do when you forgot your homework at school?
puteri [66]
Here are some ways:

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3 years ago
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Which equation matches the graph shown?
castortr0y [4]

The correct option that matches the graph is option A.

Graph is a fine representation of a network and it describes the relationship between lines and points. The length of the lines and position of the points don't count. Each object in a graph is called a knot.

The four introductory graphs used in statistics include bar, line, histogram and pie maps. The description of a graph is a illustration showing the connections between two or further effects. An illustration of graph is a pie map. noun. A wind or line showing a fine function or equation, generally drawn in a Cartesian match system.

Since it is upside down, it is the one with the negative sign in front of the x. The numbers will continue to increase in the negatives.

v=x^2-2x+1

Hence, the equation on option A matches the graph.

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4 0
2 years ago
To make the bowling team. Jacques needs a three-game average of 160. If he bowled 141 and 162 for the first two games, what scor
Aliun [14]
(141 + 162 + S) / 3 = 160

(303 + S) / 3 = 160

101 + S/3 = 160
-101 -101
S/3 = 59
*3 *3

S= 177

Jacques needs at least a 177 to get a 160 average
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4 years ago
Solve the double integral of e^y/x dy dx with outer limits as 0 and 2 and inner limits as 0 and x^2.
jek_recluse [69]
<span> lets say integrand is e^(y/x): 
∫(x = 0 to 1) ∫(y
 = 0 to x^2) e^(y/x) dy dx 
= ∫(x = 0 to 1) xe^(y/x) 
= ∫(x = 0 to 1) x(e^x - 1) dx 
= ∫(x = 0 to 1) (xe^x - x) dx 
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= 1/2. </span>
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3 years ago
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