Answer:
a.
Step-by-step explanation:
it's the odd one out;
a. 8 + 9 > 10
b. 7 + 8 < 16
c. 2 + 2 < 5
d. 10 + 11 < 22
Dy=y'*dx
=8x*dx
=8(5)*0.4
=40*0.4
=16
The answer is 6 per team with 2 left over, as (6 x 3) + 2 = 20
I thought of the largest amount that could be multiplied by 3, but the product would be less or equal to 20, that's how I got 6.
Then to find the left over remaining balls that are given out I subtracted 20-18 = 2.
5*23
Note 23 = 20 + 3
5*23 = 5*(20 + 3) and by distributive property
5*23 = 5*20 + 5*3 = 100 + 15 = 115
= 115
