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Helga [31]
3 years ago
9

1.5(x−2)−3(2−x)

Mathematics
1 answer:
adell [148]3 years ago
7 0

Answer:

1. x = 2

2. x = 61/25

Step-by-step explanation:

Solve for x:

5 (x - 2) - 3 (2 - x) = 0

-3 (2 - x) = 3 x - 6:

3 x - 6 + 5 (x - 2) = 0

5 (x - 2) = 5 x - 10:

5 x - 10 + 3 x - 6 = 0

Grouping like terms, 5 x + 3 x - 10 - 6 = (3 x + 5 x) + (-6 - 10):

(3 x + 5 x) + (-6 - 10) = 0

3 x + 5 x = 8 x:

8 x + (-6 - 10) = 0

-6 - 10 = -16:

8 x + -16 = 0

Add 16 to both sides:

8 x + (16 - 16) = 16

16 - 16 = 0:

8 x = 16

Divide both sides of 8 x = 16 by 8:

(8 x)/8 = 16/8

8/8 = 1:

x = 16/8

The gcd of 16 and 8 is 8, so 16/8 = (8×2)/(8×1) = 8/8×2 = 2:

Answer:  x = 2

_____________________________

Solve for x:

Solve for x:

3 (2 x - 7) + (7 x + 2)/3 = 0

Put each term in 3 (2 x - 7) + (7 x + 2)/3 over the common denominator 3: 3 (2 x - 7) + (7 x + 2)/3 = (9 (2 x - 7))/3 + (7 x + 2)/3:

(9 (2 x - 7))/3 + (7 x + 2)/3 = 0

(9 (2 x - 7))/3 + (7 x + 2)/3 = (9 (2 x - 7) + (7 x + 2))/3:

(9 (2 x - 7) + 2 + 7 x)/3 = 0

9 (2 x - 7) = 18 x - 63:

(18 x - 63 + 7 x + 2)/3 = 0

Grouping like terms, 18 x + 7 x - 63 + 2 = (18 x + 7 x) + (2 - 63):

((18 x + 7 x) + (2 - 63))/3 = 0

18 x + 7 x = 25 x:

(25 x + (2 - 63))/3 = 0

2 - 63 = -61:

(25 x + -61)/3 = 0

Multiply both sides of (25 x - 61)/3 = 0 by 3:

(3 (25 x - 61))/3 = 3×0

(3 (25 x - 61))/3 = 3/3×(25 x - 61) = 25 x - 61:

25 x - 61 = 3×0

0×3 = 0:

25 x - 61 = 0

Add 61 to both sides:

25 x + (61 - 61) = 61

61 - 61 = 0:

25 x = 61

Divide both sides of 25 x = 61 by 25:

(25 x)/25 = 61/25

25/25 = 1:

Answer: x = 61/25

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Step-by-step explanation:

5 0
2 years ago
30 points 1 question PLEASE HELP ME OUT I REALLY NEED IT
Pachacha [2.7K]

Answer:

p(-5/3) ≠  0 So, (3 x +5) is NOT A FACTOR of p(x)

Step-by-step explanation:

Here, the given function is p(x)=3x^5+2x^2 - 5

Now, the given root of the function is ( 3x +5)

Now, if ( 3 x +  5) = 0,

we get x = - 5/3

So, the zero of the given polynomial is x = -5/3

Then,  x = -5/3, p(x)  =0 ⇒   ( 3 x + 5) is a FACTOR of p(x)

Now, let us find the value of function at x = -5/3

Substitute x = -5/3 in the given function p(x), we get:

p(x)=3x^5+2x^2 - 5  \implies p(\frac{-5}{3})  = 3(\frac{-5}{3})^5 + 2(\frac{-5}{3})^2 - 5\\= 3(\frac{-3,125}{243}) + 2(\frac{25}{9})  - 5\\= (\frac{-3,125}{81}) + (\frac{50}{9})  - 5\\= -38.580 + 5.56  - 5  =  -38.02\\\implies p(\frac{-5}{3})  = -38.02

Now, as p(-5/3) ≠  0 So, (3x +5) is NOT A FACTOR of p(x)

6 0
3 years ago
URGENT! if ABCD is dilated by a factor of 2, the coordinate of A' would be:
koban [17]

After dilating the quadrilateral ABCD by a factor of 2 and with respect to the origin, the point A(x, y) = (-3, -1) is transformed into the point A'(x, y) = (-9, -3).

<h3>How to determine the coordinates of an image after applying a rigid transformation</h3>

First of all, dilation is a type of <em>rigid</em> transformation. <em>Rigid</em> transformations are transformations applied on <em>geometric</em> loci such that the <em>Euclidean</em> distance at every point of the construction is conserved. Vectorially speaking, the dilation is expressed by the following formula:

A'(x, y) = A(x, y) + k · [A(x, y) - O(x, y)]     (1)

Where:

  • A(x, y) - Original point
  • O(x, y) - Center of dilation
  • A'(x, y) - Resulting point
  • k - Dilation factor

If we know that A(x, y) = (-3, -1), k = 2 and O(x, y) = (0, 0), then the coordinates of A' are:

A'(x, y) = (-3, -1) + 2 · [(-3, -1) - (0, 0)]

A'(x, y) = (-3, -1) + (-6, -2)

A'(x, y) = (-9, -3)

After dilating the quadrilateral ABCD by a factor of 2 and with respect to the origin, the point A(x, y) = (-3, -1) is transformed into the point A'(x, y) = (-9, -3).

To learn more on dilations: brainly.com/question/13176891

#SPJ1

4 0
1 year ago
Find the value of x.<br> 108°<br> 40°<br> x = [?]
alexandr1967 [171]
The answer to your problem is x= 43
3 0
3 years ago
Is it a, b, c, or d don’t do explaining I just need a letter:(
andrew-mc [135]

Answer:

b

Step by Step Explanation:

4 0
2 years ago
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