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Gnesinka [82]
3 years ago
11

A 28ft ladder leans against a wall so that the base of the ladder is 5ft away from the base of the wall. How far up the wall doe

s the ladder reach?
Round to the nearest tenth.
Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0

Answer:

the top of the ladder is 27.5ft above the ground.

Step-by-step explanation:

The ladder makes an angle, θ with the ground thus forming a right angle triangle with the wall of the house.

The length of the ladder represents the hypotenuse of the right angle triangle.

The ground distance from the base of the wall to the foot of the ladder represents the adjacent side of the right angle triangle.

Therefore, to determine how high up is the top of the ladder on the wall, x, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

28² = x² + 5²

784 = x² + 25

x² = 784 - 25 = 759

x = √759 = 27.5ft

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kogti [31]

Answer:

1 = 9-3÷1/3+1

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Step-by-step explanation:

Order of operations: PEMDAS

Parentheses Exponents Multiplication Division Addition Subtraction

9-3÷1/3+1

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7 0
3 years ago
Joe gave 1/4 of his total candies to his classmate then he gave 4/6 of when he had left to his brother when he went home then he
Makovka662 [10]

Answer:

112

Step-by-step explanation:

Given: Joe gave 1/4 of his total candies to his classmate.

            Then, he gave 4/6 of when he had left to his brother.

             He gave 25% of the remaining candies to his sister.

             Finally, he only had 21 candies left.

Lets assume the total number of candies at the beginning be "x".

First, finding the number candies left after giving candies to classmate.

∴ Remaining candies=  x- x\times \frac{1}{4}

Solving it to find remaining candies after giving candies to clasmate.

⇒ Remaining candies= x-\frac{x}{4}

Taking LCD as 4

⇒ Remaining candies= \frac{4x-x}{4} = \frac{3x}{4}

∴ Remaining candies after giving candies to clasmate= \frac{3x}{4}

now, finding the candies left after giving candies to his brother.

∴ Remaining candies= \frac{3x}{4} - \frac{3x}{4} \times \frac{4}{6}

Solving it to find the remaining candies after giving candies to his brother.

⇒ Remaining candies= \frac{3x}{4} - \frac{x}{2}

Taking LCD 4

⇒ Remaining candies= \frac{3x-2x}{4} = \frac{x}{4}

∴ Remaining candies after giving candies to his brother= \frac{x}{4}

We know, Joe was left with only 21 candies after giving candies to his sister.

Therefore, putting an equation for remaining candies to find the number of candies at the beginning.

⇒\frac{x}{4} - 25\% \times \frac{x}{4} = 21

⇒\frac{x}{4} - \frac{0.25x}{4} = 21

Taking LCD 4

⇒ \frac{x-0.25x}{4} = 21

⇒ \frac{0.75x}{4} = 21

Multiplying both side by 4

⇒0.75x= 21\times 4

dividing both side by 0.75

⇒x= \frac{21\times 4}{0.75}

∴x= 112

Hence, Joe had 112 candies at the beginning.

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3 years ago
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Answer:

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Step-by-step explanation:

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It’s C. I have to put more letters just ignore this
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