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DochEvi [55]
3 years ago
12

Find each product. Then determine which conclusion can be drawn based on the results.

Mathematics
1 answer:
sweet [91]3 years ago
6 0

Answer:

B. The product of two irrational numbers can be rational or irrational.

Step-by-step explanation:

An irrational number is a number that is real and it cannot be written or expressed as a fraction.

For example , 2√3, √5 are irrational numbers.

A rational number is a number that is real and can be expressed as a fraction. It is a whole number. For example: 5, 7 are rational numbers

In the above question, we are a pair of rational and irrational number, 2 irrational numbers and we are asked to draw conclusions from their product

a) √2•√2 = √2 × √2 = √4 = 2 = rational number

b) √5•√7 = √5 × √7 = √35 = Irrational number

c) √2•18 = √2 × 18 = 18√2 = Irrational number

d) √2•√6 = √2 × √6 = √12 = Irrational number.

My conclusion from the above results is option B, which states that

B. The product of two irrational numbers can be rational or irrational.

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Answer:

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Step-by-step explanation:

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5x+4y=-14 <br>3x+6y=6<br> solve the system below by the elimation​
lana66690 [7]

Answer:

y = 4

x = -6

Step-by-step explanation:

multiply first equation by 3

3×(5x+4y)= -14 ➡ 15x + 12y = -42

multiply second equation by -5

-5×(3x+6y)= 6➡ -15x -30y = -30

now add both equations up

15x +12y -15x -30y = -42 -30 (15x will eliminate -15x)

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8 0
4 years ago
What is the equation in standard form for the circle with center (0, 0) that goes through the point (-5, 12)?
Mumz [18]

Start with the standard equation of a circle with center at (h,k) and radius r:

(x-h)^2 + (y-k)^2 = r^2. Substitute -5 for h and 12 for k:

(x-0)^2 + (y-0)^2 = r^2

Next, we substitute -5 for x and 12 for y, with the objective of determining the value of r^2:

(-5-0)^2 + (12-0)^2 = r^2. Then 25 + 144 = 169 = r^2, and r = 13.

Thus, the answer choice "x2 + y2 = 169" is the correct one.

Important: Please use " ^ " to denote exponentiation: x^2 + y^2 = 169.

6 0
3 years ago
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