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Sergeu [11.5K]
3 years ago
12

The Daily Info charges a fee of plus per week to run an ad. The People’s Paper charges per week. Write an inequality to represen

t the number of weeks an ad must run for the total cost at the Daily Info to be less expensive than the cost at the People’s Paper. Let w be the number of weeks the ad runs in the paper.
A: 650 +80w<145w
B: 145+80w<650w
C:145+650w<80w
E:650+80w<145
Mathematics
2 answers:
harina [27]3 years ago
8 0
I’m thinking it would be c sorry if it’s incorrect .
Kobotan [32]3 years ago
3 0
C sorry if incorrect
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seis manzanas y 8 peras cuestan $26. Cuánto cuesta xada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo que
vodomira [7]

Con un sistema de ecuaciones, tiene-se que:

  • Cada pera cuesta $1.
  • Cada manzana cuesta $3.

--------------

  • Usando la información dada en el texto, se construye un<em> sistema de ecuaciones</em> para encontrar el precio de cada pera e de cada manzana.
  • Yo diré que el precio de cada manzana es x y de cada pera es de y.

--------------

  • <u>La compra de 6 manzanas y 8 peras cuesta $26</u>, lo que significa que una de las ecuaciones es:

6x + 8y = 26

  • <u>Cada manzana cuesta lo triple de cada pera</u>, lo que significa que la outra ecuacione es:

x = 3y

--------------

Aplicando esta relacion en la primera ecuación, se encontra el precio de cada pera.

6x + 8y = 26

6(3y) + 8y = 26

26y = 26

y = \frac{26}{26}

y = 1

Cada pera cuesta $1.

--------------

Para cada manzana:

x = 3y = 3(1) = 3

Cada manzana cuesta $3.

Un problema similar es dado en brainly.com/question/24637096

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3 years ago
What is 5 multiplied by 7
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Answer:

5x7=35

Step-by-step explanation:

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Step-by-step explanation:

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8 0
2 years ago
On a morning of a day when the sun will pass directly​ overhead, the shadow of a 60​-ft building on level ground is 25 ft long.
AysviL [449]

Answer:

The shadow is decreasing at the rate of 3.55 inch/min

Step-by-step explanation:

The height of the building = 60ft

The shadow of the building on the level ground is 25ft long

Ѳ is increasing at the rate of 0.24°/min

Using SOHCAHTOA,

Tan Ѳ = opposite/ adjacent

= height of the building / length of the shadow

Tan Ѳ = h/x

X= h/tan Ѳ

Recall that tan Ѳ = sin Ѳ/cos Ѳ

X= h/x (sin Ѳ/cos Ѳ)

Differentiate with respect to t

dx/dt = (-h/sin²Ѳ)dѲ/dt

When x= 25ft

tanѲ = h/x

= 60/25

Ѳ= tan^-1(60/25)

= 67.38°

dѲ/dt= 0.24°/min

Convert the height in ft to inches

1 ft = 12 inches

Therefore, 60ft = 60*12

= 720 inches

Convert degree/min to radian/min

1°= 0.0175radian

Therefore, 0.24° = 0.24 * 0.0175

= 0.0042 radian/min

Recall that

dx/dt = (-h/sin²Ѳ)dѲ/dt

= (-720/sin²(67.38))*0.0042

= (-720/0.8521)*0.0042

-3.55 inch/min

Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min

8 0
4 years ago
Find the difference of (4x2 – 2x + 1) – (5x2 – 7x – 5).<br> Type your answers in the box below.
sp2606 [1]

Answer:

0.4

Step-by-step explanation:

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