All categories

3 years ago

What is the percentage of the following given numbers 35/50

Mathematics

2 answers:

sertanlavr [38]3 years ago

6 0

I'm almost sure it is 70%.....

liraira [26]3 years ago

6 0

70%

to change a fraction to a percentage multiply the fraction by 100%

$\frac{35}{50}$ × 100% = 70%

You might be interested in

If T(n)= 3n-1 what is the third term

irina [24]

T(3)=3(3)-1
T(3)=9-1
T(3)=8

answer is 8

8 0

3 years ago

Read 2 more answers

Show how to find the roots (zeros) of the function in the picture below.

Vikki [24]

Answer:

The roots (zeros) of the function are:

$x=5,\:x=-8$

Step-by-step explanation:

Given the function

$f\left(x\right)=x^2+3x-40$

substitute f(x) = 0 to determine the zeros of the function

$0=x^2+3x-40$

First break the expression x² + 3x - 40 into groups

x² + 3x - 40 = (x² - 5x) + (8x - 40)

Factor out x from x² - 5x: x(x - 5)

Factor out 8 from 8x - 40: 8(x - 5)

Thus, the expression becomes

$0=x\left(x-5\right)+8\left(x-5\right)$

switch the sides

$x\left(x-5\right)+8\left(x-5\right)=0$

Factor out common term x - 5

$(x - 5) (x + 8) = 0$

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$x-5=0\quad \mathrm{or}\quad \:x+8=0$

Solve x - 5 = 0

x - 5 = 0

adding 5 to both sides

x - 5 + 5 = 0 + 5

x = 5

solve x + 8 = 0

x + 8 = 0

subtracting 8 from both sides

x + 8 - 8 = 0 - 8

x = -8

Therefore, the roots (zeros) of the function are:

$x=5,\:x=-8$

6 0

2 years ago

Factor the quadratic expression as the product of two binomials x^2-3x-10

vovikov84 [41]

X^2+2x-5x-10
x(x+2)-5(x+2)

(x-5)(x+2)

6 0

3 years ago

How much money should be invested at 5% interest, compounded quarterly, so that 7 years later the investment will be worth $5000

vampirchik [111]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$5000\\
P=\textit{original amount deposited}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, four times}
\end{array}\to &4\\
t=years\to &7
\end{cases}
\\\\\\
5000=P\left(1+\frac{0.05}{4}\right)^{4\cdot 7}\implies 5000=P(1.0125)^{28}\\\\\\ \cfrac{5000}{(1.0125)^{28}}=P$

8 0

3 years ago

Given: KLMN is a parallelogram, LF is perpendicular to KN, LD is perpendicular to NM, angle FLD = 35. Find angles of KLMN

Kisachek [45]

The question is four parts, It is required the angles of parallelogram KLMN

So, It is required ⇒ ∠K , ∠L , ∠M and ∠N

See the attached figure which represents the explanation of the problem

========================

Part (1): Find ∠N:

==============

in the shape FLDN

∵ LF ⊥ KN ⇒⇒⇒ ∴ ∠LFN = 90°

∵ LD ⊥ NM ⇒⇒⇒ ∴ ∠LDN = 90°

∵ The sum of all angels of FLDN = 360°

∵ ∠FLD = 35°

∴ ∠FLD + ∠LDN + ∠DNF + ∠LFN = 360°

∴ 35° + 90° + ∠DNF + 90° = 360°

∴ ∠DNF = 360° - ( 90° + 90° + 35°) = 360° - 215° = 145°

∴ The measure of angle N = 145°

=============================

Part (2): Find ∠M:

==============

∵ KLMN is parallelogram , ∠N = 145°

∴ The angles N and M are supplementary angles ⇒ property of the parallelogram

∴ ∠M + ∠N = 180°

∴ ∠M = 180° - ∠N = 180° - 145° = 35°

∴ The measure of angle M = 35°

================================

Part (3): Find ∠L:

==============

∵ KLMN is parallelogram , ∠M = 35°

∴ The angles N and M are supplementary angles ⇒ property of the parallelogram

∴ ∠M + ∠KLM = 180°

∴ ∠KLM = 180° - ∠M = 180° - 35° = 145°

OR ∠KLM = ∠N = 145° ⇒⇒⇒ property of the parallelogram

∴ The measure of angle KLM = 145°

===================================

Part (4): Find ∠K:

==============∵ KLMN is parallelogram , ∠N = 35°

∴ The angles N and M are supplementary angles ⇒ property of the parallelogram

∴ ∠K + ∠N = 180°

∴ ∠K = 180° - ∠N = 180° - 145° = 35°

OR ∠K = ∠M = 35° ⇒⇒⇒ property of the parallelogram

∴ The measure of angle K = 35°

7 0

2 years ago