3 years ago

Please help me find this.

Mathematics

2 answers:

aksik [14]3 years ago

7 0

What do you mean by square I have this same question

VMariaS [17]3 years ago

4 0

Answer:

Square I think

Step-by-step explanation:

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There is a specialty store that you like to go to when you are craving jelly beans. The price is reasonable at $1.30 per pound.

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The answer is A. in the special store you spend $3 on gas + 1.30 the price of the beans times the pounds you want

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3 years ago

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fenix001 [56]

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Can't read the picture. Please take a bigger picture of the triangle.

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3 years ago

Which expression is equivalent to x² + 2x + 2?

melisa1 [442]

Answer:

$(x+1-i)(x+1+i)$

Step-by-step explanation:

$(x+1-i)(x+1+i)\\\\=(x+1)^2 -i^2~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=x^2 +2x +1 -(-1)\\\\=x^2 +2x +1+1\\\\=x^2 +2x +2$

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1 year ago

If point O represents the origin, PQ = 12 units, and P'Q' = 3 units, find the scale factor. (Note: point O represents the origin

Nataliya [291]

Answer:

1/4

Step-by-step explanation:

To transform PQR into P'Q'R, dilate the preimage by 1/4, or shrink it by a scale factor of 4 because 3/12 = 1/4

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1 year ago

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A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

3 years ago

Please help me find this.​

Please help me find this.