Each hour,
x makes b/6 bearings
y makes b/4 bearings
z makes b/3 bearings
Together, each hour, x, y and z together make
b/6+b/4+b/3=b(1/6+1/4+1/3)=b(2/12+3/12+4/12)=b(3/4)=3b/4 bearings.
Time to make b bearings =
b/(3b/4)=4/3 hours = 1 hour 20 minutes.
The greatest common factor of both x^4 and x^3 would be x^3, since the largest number of X variables that you can evenly take out between both terms is x^3 or x cubed.
Answer:
32760
Step-by-step explanation:
This is a permutation of 15 objects taken 4 at a time. To calculate this, we use the formula:

In our case, n is 15 and r is 4:
